需求说明
：需要查询出某个客户某一年那些天是有连续办理过业务
实现sql如下
：创建表：
代码如下:
create table test_num
(tyear number,
tdate date);
(tyear number,
tdate date);
测试数据
：insert into test_num
select 2014,trunc(sysdate)-1 from dual union all
select 2014,trunc(sysdate)-002 from dual union all
select 2014,trunc(sysdate)-003 from dual union all
select 2014,trunc(sysdate)-004 from dual union all
select 2014,trunc(sysdate)-005 from dual union all
select 2014,trunc(sysdate)-007 from dual union all
select 2014,trunc(sysdate)-008 from dual union all
select 2014,trunc(sysdate)-009 from dual union all
select 2013,trunc(sysdate)-120 from dual union all
select 2013,trunc(sysdate)-121 from dual union all
select 2013,trunc(sysdate)-122 from dual union all
select 2013,trunc(sysdate)-124 from dual union all
select 2013,trunc(sysdate)-125 from dual union all
select 2013,trunc(sysdate)-127 from dual union all
select 2015,trunc(sysdate)-099 from dual union all
select 2015,trunc(sysdate)-100 from dual union all
select 2015,trunc(sysdate)-101 from dual union all
select 2015,trunc(sysdate)-102 from dual union all
select 2015,trunc(sysdate)-104 from dual union all
select 2015,trunc(sysdate)-105 from dual;
写sql
: 代码如下:
SELECT TYEAR,MIN(TDATE) AS STARTDATE,MAX(TDATE),COUNT(TYEAR) AS ENDNUM
FROM (SELECT A.*,A.TDATE - ROWNUM AS GNUM
FROM (SELECT * FROM TEST_NUM ORDER BY TYEAR,TDATE) A)
GROUP BY TYEAR,GNUM
ORDER BY TYEAR,MIN(TDATE)
原文链接：https://www.f2er.com/oracle/65611.htmlFROM (SELECT A.*,A.TDATE - ROWNUM AS GNUM
FROM (SELECT * FROM TEST_NUM ORDER BY TYEAR,TDATE) A)
GROUP BY TYEAR,GNUM
ORDER BY TYEAR,MIN(TDATE)
