我有一个NSArray,数组中的每个对象都有一个groupId和一个名字.每个对象是唯一的,但是有很多与同一个groupId.有没有办法我可以拆分阵列并重新构建它,以便将名称分组为具有相应groubId的单个对象？这是数组当前的样子：
2013-03-12 20:50:05.572 appName[4102:702] the array: (
{
groupId = 1;
name = "Dan";
},{
groupId = 1;
name = "Matt";
},{
groupId = 2;
name = "Steve";
},{
groupId = 2;
name = "Mike";
},{
groupId = 3;
name = "John";
},{
groupId = 4;
name = "Kevin";
}
)
这就是我想要的样子：
2013-03-12 20:50:05.572 appName[4102:702] the array: (
{
groupId = 1;
name1 = "Dan";
name2 = "Matt";
},{
groupId = 2;
name1 = "Steve";
name2 = "Mike";
},{
groupId = 4;
name = "Kevin";
}
)
编辑：
我试过&失败了许多尝试,大多数沿着这样的事情(马虎的娱乐,但给出一个想法)：
int idNum = 0;
for (NSDictionary *arrObj in tempArr){
NSString *check1 = [NSString stringWithFormat:@"%@",[arrObj valueForKey:@"groupId"]];
NSString *check2 = [NSString stringWithFormat:@"%@",[[newDict valueForKey:@"groupId"]];
if (check1 == check2){
NSString *nameStr = [NSString stringWithFormat:@"name_%d",idNum];
[newDict setValue:[arrObj valueForKey:@"name"] forKey:nameStr];
}
else {
[newDict setValue:arrObj forKey:@"object"];
}
idNum++;
}
解决方法
NSArray *array = @[@{@"groupId" : @"1",@"name" : @"matt"},@{@"groupId" : @"2",@"name" : @"john"},@{@"groupId" : @"3",@"name" : @"steve"},@{@"groupId" : @"4",@"name" : @"alice"},@{@"groupId" : @"1",@"name" : @"bill"},@"name" : @"bob"},@"name" : @"jack"},@"name" : @"dan"},@"name" : @"kevin"},@"name" : @"mike"},@"name" : @"daniel"},];
NSMutableArray *resultArray = [NSMutableArray new];
NSArray *groups = [array valueForKeyPath:@"@distinctUnionOfObjects.groupId"];
for (NSString *groupId in groups)
{
NSMutableDictionary *entry = [NSMutableDictionary new];
[entry setObject:groupId forKey:@"groupId"];
NSArray *groupNames = [array filteredArrayUsingPredicate:[NSPredicate predicateWithFormat:@"groupId = %@",groupId]];
for (int i = 0; i < groupNames.count; i++)
{
NSString *name = [[groupNames objectAtIndex:i] objectForKey:@"name"];
[entry setObject:name forKey:[NSString stringWithFormat:@"name%d",i + 1]];
}
[resultArray addObject:entry];
}
NSLog(@"%@",resultArray);
输出：
(
{
groupId = 3;
name1 = steve;
name2 = jack;
name3 = daniel;
},{
groupId = 4;
name1 = alice;
name2 = dan;
},{
groupId = 1;
name1 = matt;
name2 = bill;
name3 = kevin;
},{
groupId = 2;
name1 = john;
name2 = bob;
name3 = mike;
}
)
