最近在看一本书《Effective OC 2.0》,今天看到有个tip是OC适中循环各自优劣性,作者最终推荐此块循环。
阅读时思考了下块循环是否方便实现内部循环终止外部循环的问题。
于是做了如下验证,代码如下:
1 // 2 // main.m 3 块循环最具优势! 4 5 Created by LongMa on 2019/4/3. 6 Copyright © 2019年. All rights reserved. 7 // 8 9 #import <Foundation/Foundation.h> 10 11 int main(int argc,const char * argv[]) { 12 @autoreleasepool { 13 NSMutableArray *lArr1 = [NSMutableArray array]; 14 NSMutableArray *lArr2 =15 for (int i = 0; i < 10; ++i) { 16 [lArr1 addObject:@(i)]; 17 [lArr2 addObject:@(i)]; 18 } 19 20 反向遍历 21 [lArr1 enumerateObjectsWithOptions:(NSEnumerationReverse) 22 usingBlock:^( NSNumber* obj,NSUInteger idx,BOOL * _Nonnull stop) { 23 NSLog(@"%@,ind:%lu",obj,(unsigned long)idx); 24 if (idx == 90) { 25 *stop = YES; 26 } 27 }]; 28 29 30 思考:里循环能否终止外循环? 31 A:可以实现!需要差异化小标和停止参数,然后在里层循环对外循环的stopOut进行操作!此时,对内循环stopIn是否操作会决定内循环是否能执行完毕。 32 33 /** 2019-04-03 01:08:30.003134+0800 块循环最具优势![3176:27943] 0,ind:0 34 2019-04-03 01:08:30.004040+0800 块循环最具优势![3176:27943] --0,1)">35 2019-04-03 01:08:30.004143+0800 块循环最具优势![3176:27943] --1,ind:1 36 2019-04-03 01:08:30.004679+0800 块循环最具优势![3176:27943] --2,ind:2 37 2019-04-03 01:08:30.004756+0800 块循环最具优势![3176:27943] --3,ind:3 38 2019-04-03 01:08:30.004819+0800 块循环最具优势![3176:27943] --4,ind:4 39 2019-04-03 01:08:30.004881+0800 块循环最具优势![3176:27943] --5,ind:5 40 2019-04-03 01:08:30.004914+0800 块循环最具优势![3176:27943] --6,ind:6 41 2019-04-03 01:08:30.004945+0800 块循环最具优势![3176:27943] --7,ind:7 42 2019-04-03 01:08:30.005036+0800 块循环最具优势![3176:27943] --8,ind:8 43 2019-04-03 01:08:30.005072+0800 块循环最具优势![3176:27943] --9,ind:9 */ 44 [lArr1 enumerateObjectsUsingBlock:^( NSNumber* obj,NSUInteger idxOut,BOOL * _Nonnull stopOut) { 45 NSLog(@"%@,ind:%lu",(unsigned long)idxOut); 46 47 if (idxOut == 2) { 48 *stopOut = YES; 49 } 50 51 [lArr2 enumerateObjectsUsingBlock:^(id _Nonnull obj,NSUInteger idxIn,1)"> _Nonnull stopIn) { 52 NSLog(--%@,1)">)idxIn); 53 if (idxIn == 354 *stopOut =55 } 56 }]; 57 58 59 * 2019-04-03 01:05:20.987109+0800 块循环最具优势![3020:25596] 0,1)">60 2019-04-03 01:05:20.987380+0800 块循环最具优势![3020:25596] --0,1)">61 2019-04-03 01:05:20.987427+0800 块循环最具优势![3020:25596] --1,1)">62 2019-04-03 01:05:20.987476+0800 块循环最具优势![3020:25596] --2,1)">63 2019-04-03 01:05:20.987499+0800 块循环最具优势![3020:25596] --3,ind:3 64 [lArr1 enumerateObjectsUsingBlock:^( NSNumber* obj,BOOL * _Nonnull stopOut) { 65 NSLog(@"%@,(unsigned long)idxOut); 66 // 67 if (idxOut == 2) { 68 *stopOut = YES; 69 70 71 72 [lArr2 enumerateObjectsUsingBlock:^(id _Nonnull obj,BOOL * _Nonnull stopIn) { 73 NSLog(@"--%@,(unsigned long)idxIn); 74 if (idxIn == 3) { 75 *stopIn = YES; 76 *stopOut = YES; 77 78 79 80 }]; 81 82 83 } 84 return 0; 85 }
运行上面代码可见:
可以实现!需要差异化小标和停止参数,然后在里层循环对外循环的stopOut进行操作!此时,对内循环stopIn是否操作会决定内循环是否能执行完毕。