在搞乱
Swift时,我注意到当64位整数溢出时,我收到以下错误：
file:///Users/user/Documents/playground/MyPlayground.playground/: error: Playground execution aborted: Execution was interrupted,reason: EXC_BAD_INSTRUCTION (code=EXC_I386_INVOP,subcode=0x0).
func fibonacci(which: Int) -> (fibOf: Int,isEqualTo: Int) {
var i = 1,j = 1
for var k = 2; k < which; k += 1 {
let tmp = i + j // this line is highlighted when error occurs
j = i
i = tmp
}
return (which,i)
}
print (fibonacci(92))
print (fibonacci(93)) // this triggers an error
第一个调用,即92作为参数,将运行良好.但是,当提供93值时,我得到了无关的EXC_BAD_INSTRUCTION错误.这是一个错误还是什么？通常我会期望它溢出.
解决方法
这是预期的行为.如果要溢出,则需要使用
overflow operators.
>溢出添加(&)>溢出减法(& 原文链接：https://www.f2er.com/iOS/328236.html
