我有一个批处理脚本,它将整行搜索字符串打印到一个文本文件中.
for %%i in (log.txt) do ( FINDSTR /G:pattern.txt %%i >> output.txt )
例：
pattern.txt包含搜索字符串ERROR,以下是log.txt中的示例文本
2013-06-30 02:17:55,562 INFO Service started 2013-06-30 02:17:55,578 INFO Sending mail... 2013-06-30 02:17:55,578 DEBUG Element value: 1 2013-06-30 02:17:55,578 ERROR error occurred and message is "" 2013-06-30 02:17:55,578 DEBUG bit version: 8 2013-06-30 02:17:55,578 INFO Service stopped
只要在log.txt中找到字符串ERROR,上面的批处理脚本就会打印每行文本.所以,output.txt看起来会有如下所示的行
2013-06-30 02:17:55,578 ERROR error occurred and message is ""
如何只打印上一行和下一行搜索字符串,如下所示：
2013-06-30 02:17:55,578 DEBUG bit version: 8
提前致谢.
@echo off
setlocal EnableDelayedExpansion
rem Assemble the list of line numbers
set numbers=
for /F "delims=:" %%a in ('findstr /I /N /C:"error occurred" log.txt') do (
set /A before=%%a-1,after=%%a+1
set "numbers=!numbers!!before!: !after!: "
)
rem Search for the lines
(for /F "tokens=1* delims=:" %%a in ('findstr /N "^" log.txt ^| findstr /B "%numbers%"') do echo %%b) > output.txt
