我想从URL中取出一个参数,而不知道它是哪个参数,然后再次重新组合URL.
我想这不是很难用CGI或者URI自己编写的东西,但是我想像这样的功能已经存在了.有什么建议么？
在：
http://example.com/path?param1=one¶m2=2¶m3=something3
日期：
http://example.com/path?param2=2¶m3=something3
解决方法
可寻址的宝石会很好地做到这一点;请看“天男”的上级答案.但是,如果你想自己滚动,这是怎么回事.唯一要求这个代码优雅的是它在一个方法中隐藏了丑陋：
#!/usr/bin/ruby1.8
def reject_param(url,param_to_reject)
# Regex from RFC3986
url_regex = %r"^(([^:/?#]+):)?(//([^/?#]*))?([^?#]*)(\?([^#]*))?(#(.*))?$"
raise "Not a url: #{url}" unless url =~ url_regex
scheme_plus_punctuation = $1
authority_with_punctuation = $3
path = $5
query = $7
fragment = $9
query = query.split('&').reject do |param|
param_name = param.split(/[=;]/).first
param_name == param_to_reject
end.join('&')
[scheme_plus_punctuation,authority_with_punctuation,path,'?',query,fragment].join
end
url = "http://example.com/path?param1=one¶m2=2¶m3=something3"
p url
p reject_param(url,'param2')
# => "http://example.com/path?param1=one¶m2=2¶m3=something3"
# => "http://example.com/path?param1=one¶m3=something3"