下列…
require 'yaml'
test = "I'm a b&d string"
File.open('test.yaml','w') do |out|
out.write(test.to_yaml)
end
……输出……
--- this is a b&d string
我怎样才能输出它
--- 'this is a b&d string'
???
解决方法
如果要在YAML中存储转义字符串,
在将其转换为YAML之前使用#inspect转义它：
在将其转换为YAML之前使用#inspect转义它：
irb> require 'yaml'
=> true
irb> str = %{This string's a little complicated,but it "does the job" (man,I hate scare quotes)}
=> "This string's a little complicated,but it \"does the job\" (man,I hate scare quotes)"
irb> puts str
This string's a little complicated,I hate scare quotes)
=> nil
irb> puts str.inspect
"This string's a little complicated,I hate scare quotes)"
=> nil
irb> puts str.to_yaml
--- This string's a little complicated,I hate scare quotes)
=> nil
irb> puts str.inspect.to_yaml
--- "\"This string's a little complicated,but it \\\"does the job\\\" (man,I hate scare quotes)\""
=> nil
除非必须,YAML不引用字符串.它引用了字符串,如果它们包含了它会在未加引号存储的情况下会丢失的东西 – 比如周围的引号字符或尾随或前导空格：
irb> puts (str + " ").to_yaml
--- "This string's a little complicated,I hate scare quotes) "
=> nil
irb> puts %{"#{str}"}.to_yaml
--- "\"This string's a little complicated,I hate scare quotes)\""
=> nil
irb> puts (" " + str).to_yaml
--- " This string's a little complicated,I hate scare quotes)"
=> nil
但是,作为YAML消费者,字符串是否引用对您来说无关紧要.你永远不应该自己解析YAML文本 – 把它留给库.如果你需要在YAML文件中引用字符串,那对我来说闻起来很糟糕.
你的字符串中是否包含’&’并不重要,YAML会保留字符串：
irb> test = "I'm a b&d string" => "I'm a b&d string" irb> YAML::load(YAML::dump(test)) => "I'm a b&d string" irb> YAML::load(YAML::dump(test)) == test => true