ruby-on-rails – 将两个命名范围与OR(而不是AND)组合在一起

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我想找到所有注释,其主体是:

>等于“?”
>或
>喜欢“[?]”

最好的方法是什么?

我想尽可能使用SearchLogic,但是SearchLogic允许您执行以下各项操作:

> Annotation.body_equals(‘?’)
> Annotation.body_like(‘[?]’)

并且你总是可以将它们链接在一起:Annotation.body_equals(‘?’).body_like(‘[?]’)

我不确定如何将它们与OR结合起来.

Note that you can combine named scopes with OR if their argument is the same.例如,我可以这样做:

Annotation.body_equals_or_body_like('?')

但这没有用.

请注意,我并不依赖于SearchLogic,但对于不需要破坏其抽象的解决方案来说,它会很棒.

解决方法

我找不到任何简单的解决方案,但这个问题引起了我的兴趣,所以我推出了自己的解决方案:
class ActiveRecord::Base

  def self.or_scopes(*scopes)
    # Cleanup input
    scopes.map! do |scope|
      scope = scope.respond_to?(:to_a) ? scope.to_a : [*scope]
      scope.unshift(scope.shift.to_sym)
    end

    # Check for existence of scopes
    scopes.each{|scope| raise ArgumentError,"invalid scope: #{scope.first}" unless self.scopes.has_key?(scope.first) }

    conditions = scopes.map do |scope|
      scope = self.scopes[scope.first].call(self,*scope[1..-1])
      self.merge_conditions(scope.proxy_options[:conditions])
    end

    or_conditions = conditions.compact.join(" OR ")

    merged_scopes = scopes.inject(self){|merged,scope| merged.scopes[scope.first].call(self,*scope[1..-1]) }

    # We ignore other scope types but so does named_scopes
    find_options = merged_scopes.scope(:find).merge(:conditions => or_conditions)

    self.scoped(find_options)
  end

end

请考虑以下设置:

class Person < ActiveRecord::Base
  named_scope :men,:conditions => { :sex => 'M' }
  named_scope :women,:conditions => { :sex => 'F' }
  named_scope :children,:conditions => "age < 18"
  named_scope :named,lambda{|name|
    { :conditions => { :name => name } }
  }
end

您可以使用一系列范围的名称调用它:

Person.or_scopes(:women,:children)

这将返回如下范围:

Person.or_scopes(:women,:children).proxy_options
# => {:conditions=>"(`people`.`sex` = 'F') OR (age < 18)"}

当范围需要参数时,您也可以使用数组数组调用它:

Person.or_scopes(:women,[:named,'Sue']).proxy_options
# => {:conditions=>"(`people`.`sex` = 'F') OR (`people`.`name` = 'Sue')"}

在您的案例中,您可以使用以下内容

Annotation.or_scopes([:body_equals,'?'],[:body_like,'[?']).all
原文链接:https://www.f2er.com/ruby/268695.html

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