当我试图在它们的数组中检测某个字符串时,我遇到了一个奇怪的问题.谁知道这里发生了什么？
(rdb:1) p magic_string "Time Period" (rdb:1) p magic_string.class String (rdb:1) p magic_string == "Time Period" false (rdb:1) p "Time Period".length 11 (rdb:1) p magic_string.length 14 (rdb:1) p magic_string[0].chr "\357" (rdb:1) p magic_string[1].chr "\273" (rdb:1) p magic_string[2].chr "\277" (rdb:1) p magic_string[3].chr "T"
解决方法
您的字符串在开头包含3个字节(BOM),表示编码为UTF-8.
Q: What is a BOM?
A: A byte order mark (BOM) consists of the character code U+FEFF at
the beginning of a data stream,where it can be used as a signature
defining the byte order and encoding form,primarily of unmarked
plaintext files. Under some higher level protocols,use of a BOM may
be mandatory (or prohibited) in the Unicode data stream defined in
that protocol.