用于捕获不同日期格式的正则表达式

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我的任务是在电子邮件中捕获行程的日期,但是给出的日期都是不同的格式,我想我需要帮助才能找出是否有任何方法可以捕获以下格式:

02 APR
APR 02
2 APR
APR 2
2nd APR
APR 2nd
2nd April
April 2nd
APR 12th
April 12th
12th April
April 13-16
13-16 April
APR 13-16
13-16 APR
April 13th-16th
13th-16th April
APR 13th-16th
13th-16th APR

我已经尝试了很多方法,但是因为我不能理解或理解
新手到正则表达式.

我能得到的最接近的是:

(\d*)-(\d*) APR|April \d*\d*

编辑 – 发现我错过了更多的格式.

4月13日至16日

4月13日至16日

13/16 APR

我尝试过使用以下内容

(Jan(?:uary)?|Feb(?:ruary)?|Mar(?:ch)?|Apr(?:il)?|May|Jun(?:e)?|Jul(?:y)?|Aug(?:ust)?|Sep(?:tember)?|Oct(?:ober)?|Nov(?:ember)?|Dec(?:ember)?)\ *\d+(?:[nr]d|th|st)?(?: * \d+(?:[nr]d|th|st)?)?|\d+(?:[nr]d|th|st)?(?: . \d+(?:[nr]d|th|st)?)?\ *(?:Jan(?:uary)?|Feb(?:ruary)?|Mar(?:ch)?|Apr(?:il)?|May|Jun(?:e)?|Jul(?:y)?|Aug(?:ust)?|Sep(?:tember)?|Oct(?:ober)?|Nov(?:ember)?|Dec(?:ember)?)

可以用空格或没有空格捕获日期.
有没有办法捕获所有格式,并将日期分为’ – ‘,’/’,’〜’和输出/写入一个标准化格式?

(Group 1 Date)-Month (Group 2 Date)-Month eg: 13-Apr 16-Apr

感谢您的善意建议和意见.

解决方法

我想出了这个正则表达式:

(?:APR|April)\ *\d+(?:[nr]d|th|st)?(?:-\d+(?:[nr]d|th|st)?)?|\d+(?:[nr]d|th|st)?(?:-\d+(?:[nr]d|th|st)?)?\ *(?:APR|April)

详情请见:Regex101

也许它有点矫枉过正,但我​​想出了这个与任何月份匹配的正则表达式:

(?:January|JAN|February|FEB|March|MAR|April|APR|May|MAY|June|JUN|July|JUL|August|AUG|September|SEP|October|OCT|November|NOV|December|DEC)\ *\d+(?:[nr]d|th|st)?(?:-\d+(?:[nr]d|th|st)?)?|\d+(?:[nr]d|th|st)?(?:-\d+(?:[nr]d|th|st)?)?\ *(?:January|JAN|February|FEB|March|MAR|April|APR|May|MAY|June|JUN|July|JUL|August|AUG|September|SEP|October|OCT|November|NOV|December|DEC)

如果您需要详细信息,请在此处查看:Regex101

使用WiktorStribiżew的技巧改进版本:

(?:Jan(?:uary)?|Feb(?:ruary)?|Mar(?:ch)?|Apr(?:il)?|May|Jun(?:e)?|Jul(?:y)?|Aug(?:ust)?|Sep(?:tember)?|Oct(?:ober)?|Nov(?:ember)?|Dec(?:ember)?)\ *\d+(?:[nr]d|th|st)?(?:-\d+(?:[nr]d|th|st)?)?|\d+(?:[nr]d|th|st)?(?:-\d+(?:[nr]d|th|st)?)?\ *(?:Jan(?:uary)?|Feb(?:ruary)?|Mar(?:ch)?|Apr(?:il)?|May|Jun(?:e)?|Jul(?:y)?|Aug(?:ust)?|Sep(?:tember)?|Oct(?:ober)?|Nov(?:ember)?|Dec(?:ember)?)

详情请见:Regex101它匹配每个monthes,它使用更少的步骤(更有效)但是,你需要确保你不区分大小写

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