我设置了一个导航器,从一个屏幕到另一个屏幕.按下行时我可以打开一个新屏幕,但我无法想象如何将数据传递到这个新屏幕.

我在index.android.js中设置了一个导航器

import React from 'react';
import {
  AppRegistry,Navigator,} from 'react-native';

import ContactList from './src/containers/ContactList.js';

function MyIndex() {
  return (
    <Navigator
      initialRoute={{ name: 'index',component: ContactList }}
      renderScene={(route,navigator) => {
        if (route.component) {
          return React.createElement(route.component,{ navigator });
        }

        return undefined;
      }}
    />
  );
}

AppRegistry.registerComponent('reactest',() => MyIndex);

首先,我显示一个带有按钮和空列表视图的屏幕(ContactList.js),按下按钮后,我获取了一些用于更新列表视图的JSON数据：

import React,{ Component,PropTypes } from 'react';
import {
  Text,View,TouchableOpacity,TouchableHighlight,ListView,Image,} from 'react-native';

import styles from '../../styles';
import ContactDetails from './ContactDetails';

const url = 'http://api.randomuser.me/?results=15&seed=azer';

export default class ContactList extends Component {
  static propTypes = {
    navigator: PropTypes.object.isrequired,}
  constructor(props) {
    super(props);

    const datasource = new ListView.DataSource({ rowHasChanged: (r1,r2) => r1 !== r2 });
    this.state = {
      jsonData: datasource.cloneWithRows([]),ds: datasource,};
  }
  _handlePress() {
    return fetch(url)
      // convert to json
      .then((response) => response.json())
      // do some string manipulation on json
      .then(({ results }) => {
        const newResults = results.map((user) => {
          const newUser = {
            ...user,name: {
              title: `${user.name.title.charAt(0).toUpperCase()}${user.name.title.slice(1)}`,first: `${user.name.first.charAt(0).toUpperCase()}${user.name.first.slice(1)}`,last: `${user.name.last.charAt(0).toUpperCase()}${user.name.last.slice(1)}`,},};

          return newUser;
        });

        return newResults;
      })
      // set state
      .then((results) => {
        this.setState({
          jsonData: this.state.ds.cloneWithRows(results),});
      });
  }
  renderRow(rowData: string) {
    return (
      <TouchableHighlight
        onPress={() => {
          this.props.navigator.push({
            component: ContactDetails,});
        }}
      >
        <View style={styles.listview_row}>
          <Image
            source={{ uri: rowData.picture.thumbnail }}
            style={{ height: 48,width: 48 }}
          />
          <Text>
            {rowData.name.title} {rowData.name.first} {rowData.name.last}
          </Text>
        </View>
      </TouchableHighlight>
    );
  }
  render() {
    const view = (
      <View style={styles.container}>
        <TouchableOpacity
          onPress={() => this._handlePress()}
          style={styles.button}
        >
          <Text>Fetch results?</Text>
        </TouchableOpacity>
        <ListView
          enableEmptySections
          dataSource={this.state.jsonData}
          renderRow={(rowData) => this.renderRow(rowData)}
          onPress={() => this._handleRowClick()}
        />
      </View>
    );

    return view;
  }
}

当按下一行时,它会打开一个新的屏幕ContactDetails.js,它应该显示用户的数据：

import React,{
} from 'react';

import {
  Text,} from 'react-native';

import styles from '../../styles';

export default function ContactDetails() {
  return (
    <View style={styles.container}>
      <Text>{this.props.title}</Text>
      <Text>{this.props.first}</Text>
      <Text>{this.props.last}</Text>
    </View>
  );
}

此时我收到了这个错误：

undefined is not an object (evaluating ‘this.props.title’)

我尝试了很多东西,比如：

this.props.navigator.push({
    component: ContactDetails,title: rowData.name.title,first: rowData.name.first,last: rowData.name.last,});

要么

this.props.navigator.push({
    component: ContactDetails,props: {
        title: rowData.name.title,}
});

要么

this.props.navigator.push({
    component: ContactDetails,passProps: {
        title: rowData.name.title,}
});

但无济于事.

我还读到我应该使用redux.难道我做错了什么 ？

编辑：问题在这里：

<TouchableHighlight
    onPress={() => {
      this.props.navigator.push({
        component: ContactDetails,});
    }}
>

我想我应该在那里传递一些参数,但无论我在上面尝试过什么都失败了.