PHP 利用日期函数格式化一个UNIX时间为文本

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PHP日期函数 - 格式化一个UNIX时间为文本
日期函数可以根据指定的格式将一个unix时间格式化成想要的文本输出
使用到函数语法如下

/**
 * PHP日期函数 - 格式化一个UNIX时间为文本
 *
 * @param 
 * @arrange 512-笔记网: www.512Pic.com
 **/
string date (string $Format);
string date (string $Format,int $Time);
/***   来自编程之家 jb51.cc(jb51.cc)   ***/
下面是演示代码

/**
 * PHP日期函数 - 格式化一个UNIX时间为文本
 *
 * @param 
 * @arrange 512-笔记网: www.512Pic.com
 **/
<?PHP
echo "When this page was loaded,\n";
echo 'It was then ',date ('r'),"\n";
echo 'The currend date was ',date ('F j,Y'),date ('M j,date ('m/d/y'),"\n";
echo 'The currend date was the ',date ('jS \o\f M,"\n";
echo 'The currend time was ',date ('g:i:s A T'),date ('H:i:s O'),"\n";
echo date ('Y');
date ('L')?(print ' is'):(print ' is not');
echo " a leap year\n";
echo time ('U')," seconds had elapsed since January 1,1970.\n";
?>
/***   来自编程之家 jb51.cc(jb51.cc)   ***/
输出结果如下

/**
 * PHP日期函数 - 格式化一个UNIX时间为文本
 *
 * @param 
 * @arrange 512-笔记网: www.512Pic.com
 **/
It was then Sat,26 Dec 2009 07:09:51 +0000
The currend date was December 26,2009
The currend date was Dec 26,2009
The currend date was 12/26/09
The currend date was the 26th of Dec,2009
The currend time was 7:09:51 AM GMT
The currend time was 07:09:51 +0000
2009 is not a leap year
1261811391 seconds had elapsed since January 1,1970.
/***   来自编程之家 jb51.cc(jb51.cc)   ***/

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