PHP DataGrid 实现代码
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PHP DataGrid 实现代码，
前端之家小编觉得挺不错的，现在分享给大家，也给大家做个参考。
由于需要连接Oracle所以从二次开发和页面样式来说个人觉得PHPMyDataGrid还是比较好上手。本篇首先介绍基于MysqL的使用方法，再简单介绍对于Oracle连接（基于sqlrelay）的二次开发。
1. 创建测试数据库和表
<div class="codetitle">
<a style="CURSOR: pointer" data="51430" class="copybut" id="copybut51430" onclick="doCopy('code51430')"> 代码如下: <div class="codebody" id="code51430">
create database
guru; USE
guru; CREATE TABLE
employees (
id int(6) NOT NULL auto_increment,
name char(20) default NULL,
lastname char(20) default NULL,
salary float default NULL,
age int(2) default NULL,
afiliation date default NULL,
status int(1) default NULL,
active tinyint(1) default NULL,
workeddays int(2) default NULL,
photo char(30) default NULL,
PRIMARY KEY (
id)
) insert into
employees (
id,
name,
lastname,
salary,
age,
afiliation,
status,
active,
workeddays,
photo)
values (1,'Ana','Trujillo',2000,45,'2005-05-13',1,10,'1.jpg');
insert into
employees (
id,
photo)
values (2,'Jennifer','Aniston',3500,23,'2004-10-22','2.jpg');
insert into
employees (
id,
photo)
values (3,'Michael','Norman',1200,19,'2007-01-10',5,'3.jpg');
insert into
employees (
id,
photo)
values (4,'Vanessa','Black',6500,31,'2000-11-05',30,'4.jpg');
insert into
employees (
id,
photo)
values (5,'Strauss',3200,'2006-10-21',2,22,'5.jpg');
insert into
employees (
id,
photo)
values (6,'William','Brown',2300,21,'2001-03-10',3,'6.jpg');
insert into
employees (
id,
photo)
values (7,'Lucca','Normany',2800,36,'2006-10-02',20,'7.jpg');
mydatagrid.class.
.
