php 判断访客是否为搜索引擎蜘蛛的函数代码

前端之家收集整理的这篇文章主要介绍了php 判断访客是否为搜索引擎蜘蛛的函数代码前端之家小编觉得挺不错的,现在分享给大家,也给大家做个参考。

<div class="codetitle"><a style="CURSOR: pointer" data="50506" class="copybut" id="copybut50506" onclick="doCopy('code50506')"> 代码如下:

<div class="codebody" id="code50506">
/*
判断是否为搜索引擎蜘蛛

@author Eddy
@return bool
/
function isCrawler() {
$agent= strtolower($_SERVER['HTTP_USER_AGENT']);
if (!empty($agent)) {
$spiderSite= array(
"TencentTraveler",
"Baiduspider+",
"BaiduGame",
"Googlebot",
"msnbot",
"Sosospider+",
"Sogou web spider",
"ia_archiver",
"Yahoo! Slurp",
"YoudaoBot",
"Yahoo Slurp",
"MSNBot",
"Java (Often spam bot)",
"BaiDuSpider",
"Voila",
"Yandex bot",
"BSpider",
"twiceler",
"Sogou Spider",
"Speedy Spider",
"Google AdSense",
"Heritrix",
"Python-urllib",
"Alexa (IA Archiver)",
"Ask",
"Exabot",
"Custo",
"OutfoxBot/YodaoBot",
"yacy",
"SurveyBot",
"legs",
"lwp-trivial",
"Nutch",
"StackRambler",
"The web archive (IA Archiver)",
"Perl tool",
"MJ12bot",
"Netcraft",
"MSIECrawler",
"WGet tools",
"larbin",
"Fish search",
);
foreach($spiderSite as $val) {
$str = strtolower($val);
if (strpos($agent,$str) !== false) {
return true;
}
}
} else {
return false;
}
}
网上倒是能搜到一大把,不过都是千篇一律的复制来复制去的,也不够全面,我这里整理了一份比较全面的代码: <div class="codetitle"><a style="CURSOR: pointer" data="42220" class="copybut" id="copybut42220" onclick="doCopy('code42220')"> 代码如下:
<div class="codebody" id="code42220">
function is_spider(){
$robot = 0;
$USER_AGENT = strtolower($_SERVER['HTTP_USER_AGENT']);
if(strpos($USER_AGENT,"bot")) $robot = 1;
if(strpos($USER_AGENT,"spider")) $robot = 1;
if(strpos($USER_AGENT,"slurp")) $robot = 1;
if(strpos($USER_AGENT,"mediapartners-google")) $robot = 1;
if(strpos($USER_AGENT,"fast-webcrawler")) $robot = 1;
if(strpos($USER_AGENT,"altavista")) $robot = 1;
if(strpos($USER_AGENT,"ia_archiver")) $robot = 1;
if($robot == 1){
//do something
}
return '';
}

原文链接:https://www.f2er.com/php/27717.html

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