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• 前端之家
• PHP
• 用PHP实现 上一篇、下一篇的代码

<div class="codebody" id="code99467">
<?PHP
//----显示上一篇、下一篇文章代码 START---- $sql_former = "select from article where id<$id order by id desc "; //上一篇文章sql语句。注意是倒序，因为返回结果集时只用了第一篇文章，而不是最后一篇文章
$sql_later = "select from article where id>$id "; //下一篇文章sql语句
$queryset_former = MysqL_query($sql_former); //执行sql语句
if(MysqL_num_rows($queryset_former)){ //返回记录数，并判断是否为真，以此为依据显示结果
$result = MysqL_fetch_array($queryset_former);
echo "上一篇 ". $result[title]."
";
} else {echo "上一篇 没有了
";} $queryset_later = MysqL_query($sql_later);
if(MysqL_num_rows($queryset_later)){
$result = MysqL_fetch_array($queryset_later);
echo "下一篇 ". $result['title']."
";
} else {echo "下一篇 没有了
";}
?>