本文实例讲述了PHP检测用户语言的方法。分享给大家供大家参考。具体如下：
0.8
$langs = array_combine($lang_parse[1],$lang_parse[4]);
// set default to 1 for any without q factor
foreach ($langs as $lang => $val) {
if ($val === '') $langs[$lang] = 1;
}
// sort list based on value
arsort($langs,SORT_NUMERIC);
}
}
//extract most important (first)
foreach ($langs as $lang => $val) { break; }
//if complex language simplify it
if (stristr($lang,"-")) {$tmp = explode("-",$lang); $lang = $tmp[0]; }
return $lang;
}
希望本文所述对大家的PHP程序设计有所帮助。
原文链接：https://www.f2er.com/php/21783.html