namespace MyApp;
class MysqLi extends \MysqLi {
    public function query($query,$resultmode = null) {
        // This needs to return a MysqLiResult or a boolean
    }
}
class MysqLiResult extends \MysqLi_result {
}

这样做我可以返回一个MysqLiResult对象,但我无法弄清楚如何为非基于选择的查询返回一个布尔值：

public function query($query,$resultmode = null) {
    $this->real_query($query); 
    return new MysqLiResult($this);
}

更新：

这是我最终使用的：

class MysqLi extends \MysqLi {

    public function query($query,$resultmode = null) {
        $result = parent::query($query,$resultmode);
        return is_bool($result) ? $result : new MysqLiResult($result);
    }

}


class MysqLiResult {

    private $result;

    public function __construct(MysqLi_result $result) {
        $this->result = $result;
    }

    public function __call($name,$arguments) {
        return call_user_func_array(array($this->result,$name),$arguments);
    }

    public function __set($name,$value) {
        $this->result->$name = $value;
    }

    public function __get($name) {
        return $this->result->$name;
    }

}