假设我有以下2个日期,开始日期和结束日期：
Year-Month-Day Hours:Minutes:Seconds Start Date: 2010-12-03 14:04:41 Expiry Date: 2010-12-06 12:59:59
我怎么能用PHP减去两个日期并留下类似的东西：
差异：-3天,2分18秒(例如,如果有效期超过3天).
这基于众多在线示例;如果你打开谷歌,你会看到类似的代码.
原文链接：https://www.f2er.com/php/138517.htmlfunction timeSince($dateFrom,$dateTo) {
// array of time period chunks
$chunks = array(
array(60 * 60 * 24 * 365,'year'),array(60 * 60 * 24 * 30,'month'),array(60 * 60 * 24 * 7,'week'),array(60 * 60 * 24,'day'),array(60 * 60,'hour'),array(60,'minute'),);
$original = strtotime($dateFrom);
$now = strtotime($dateTo);
$since = $now - $original;
$message = ($now < $original) ? '-' : null;
// If the difference is less than 60,we will show the seconds difference as well
if ($since < 60) {
$chunks[] = array(1,'second');
}
// $j saves performing the count function each time around the loop
for ($i = 0,$j = count($chunks); $i < $j; $i++) {
$seconds = $chunks[$i][0];
$name = $chunks[$i][1];
// finding the biggest chunk (if the chunk fits,break)
if (($count = floor($since / $seconds)) != 0) {
break;
}
}
$print = ($count == 1) ? '1 ' . $name : $count . ' ' . $name . 's';
if ($i + 1 < $j) {
// now getting the second item
$seconds2 = $chunks[$i + 1][0];
$name2 = $chunks[$i + 1][1];
// add second item if it's greater than 0
if (($count2 = floor(($since - ($seconds * $count)) / $seconds2)) != 0) {
$print .= ($count2 == 1) ? ',1 ' . $name2 : ',' . $count2 . ' ' . $name2 . 's';
}
}
return $message . $print;
}
它旨在显示给定时间和当前时间之间的差异,但我做了一些细微的改动,以显示两次之间的差异.您可能希望将“之前”的后缀的输出更改为“差异：”的前缀.
