$friday = strtotime('Next Friday',time());
$saturday = strtotime('Next Saturday',time());
$friday = strtotime('+1 Week',$friday);
$saturday = strtotime('+1 Week',$saturday);

当然你应该调整它以完全按照自己的意愿行事,但这与我试图做的不同.

另请注意,strtotime会为您提供时间戳.要找出使用日期：

date('Y-m-d',$friday)

另一件需要知道的是Next< dayofweek>将您的当前日期从搜索中排除,因此如果您还想要包含当天,您可以这样做：

$friday = strtotime('Next Friday',strtotime('-1 Day',time()));

这是一个完整的工作脚本,完全符合您的要求.

<?PHP
// prevent multiple calls by retrieving time once //
$now = time();
$aYearLater = strtotime('+1 Year',$now);

// fill this with dates //
$allDates = Array();

// init with next friday and saturday //
$friday = strtotime('Next Friday',$now));
$saturday = strtotime('Next Saturday',$now));

// keep adding days untill a year has passed //
while(1){
    if($friday > $aYearLater)
        break 1;
    $allDates[] = date('Y-m-d',$friday);
    if($saturday > $aYearLater)
        break 1;
    $allDates[] = date('Y-m-d',$saturday);

    $friday = strtotime('+1 Week',$friday);
    $saturday = strtotime('+1 Week',$saturday);
}

//XXX: debug
var_dump($allDates);

?>

祝你好运,Alin