php – 以编程方式确定图像的人类可读颜色(例如红色,绿色等)

我试图想出一个脚本,它将以编程方式运行图像并告诉我它的主要颜色.

目前,脚本获取每个像素的RGB值.将它们与预定义规则进行比较,并尝试计算每种颜色的像素数.

我的问题是脚本有点受打击.有没有人知道更好的方法(可能使用更容易翻译成英语的不同颜色编码系统)或通过RGB定义颜色的现有规则集？

<?PHP
$file = "8629.jpg";

$colors = array("Red" => array("rel" => true,"r" => 0.65,"g" => 0.09,"b" => 0.25,"var" => 0.3),"Blue" => array("rel" => true,"r" => 0.21,"g" => 0.32,"b" => 0.46,"Green" => array("rel" => true,"r" => 0,"g" => 0.67,"b" =>  0.33,"Black" => array("rel" => false,"g" => 0,"b" =>  0,"var" => 30),"White" => array("rel" => false,"r" => 255,"g" => 255,"b" =>  255,"var" => 30));                 

$total = 0;

$im = imagecreatefromjpeg($file);
$size = getimagesize($file);

if (!$im) {
    exit("No image found.");
}

for ($x = 1; $x <= $size[0]; $x++) {
    for($y = 1; $y <= $size[1]; $y++) {
        $rgb = imagecolorat($im,$x,$y);
        $r = ($rgb >> 16) & 0xFF;
        $g = ($rgb >> 8) & 0xFF;
        $b = $rgb & 0xFF;

        $colorTotal = $r + $g + $b;

        $rRatio = $r > 0 ? $r / $colorTotal : 0;
        $gRatio = $g > 0 ? $g / $colorTotal : 0;
        $bRatio = $b > 0 ? $b / $colorTotal : 0;

        foreach($colors as $key => $color) {
            if ($color["rel"]) {
                if ((($color["r"] - $color["var"]) <= $rRatio && $rRatio <= ($color["r"] + $color["var"])) &&
                    (($color["g"] - $color["var"]) <= $gRatio && $gRatio <= ($color["g"] + $color["var"])) &&
                    (($color["b"] - $color["var"]) <= $bRatio && $bRatio <= ($color["b"] + $color["var"]))) {

                    $colourCount[$key]++;
                    $total++;
                }
            } else {
                if ((($color["r"] - $color["var"]) <= $r && $r <= ($color["r"] + $color["var"])) &&
                    (($color["g"] - $color["var"]) <= $g && $g <= ($color["g"] + $color["var"])) &&
                    (($color["b"] - $color["var"]) <= $b && $b <= ($color["b"] + $color["var"]))) {

                    $colourCount[$key]++;
                    $total++;
                }
            }
        }
    }
}

var_dump($colourCount);

foreach($colourCount as $key => $color) {
    $colourPrecent[$key] = $color / $total;
}

arsort($colourPrecent);
var_dump($colourPrecent);

foreach($colourPrecent as $key => $color) {
    if ($prevVal) {
        if ($color < ($prevVal - 0.1)) {
            break;
        }
    }

    $primary[] = $key;
    $prevVal = $color;
}

echo("The primary colours in this image are " . implode(" and ",$primary));

?>

解决方案是按照赫伯特的建议将RGB转换为HSL.转换为人类的功能仍然需要稍微调整/完成,但这里是：

function hslToHuman($h,$s,$l) {

$colors = array();

// Gray
if ($s <= 10 && (9 <= $l && $l <= 90)) {
    $colors[] = "gray";
}

$l_var = $s / 16;

// White
$white_limit = 93;
if (($white_limit + $l_var) <= $l && $l <= 100) {
    $colors[] = "white";
}

// Black
$black_limit = 9;
if (0 <= $l && $l <= ($black_limit - $l_var)) {
    $colors[] = "black";
}

// If we have colorless colors stop here
if (sizeof($colors) > 0) {
    return $colors;
}

// Red
if (($h <= 8 || $h >= 346)) {
    $colors[] = "red";
}

// Orange && Brown
// TODO

// Yellow
if (40 <= $h && $h <= 65) {
    $colors[] = "yellow";
}

// Green
if (65 <= $h && $h <= 170) {
    $colors[] = "green";
}

// Blue
if (165 <= $h && $h <= 260) {
    $colors[] = "blue";
}

// Pink && Purple
// TODO

return $colors;
}

原文链接：https://www.f2er.com/php/137468.html

php – 以编程方式确定图像的人类可读颜色(例如红色,绿色等)

猜你在找的PHP相关文章