例1:
在一个简单的例子中,说我们有两个人,一个红球和一个绿球.人1可以选择任一球,但是人2只能选择绿球.这可以说明如下:
- Person 1: RG
- Person 2: G
因为我们知道人2必须选择绿球,这意味着人1不能选择那个球,因此必须选择红球.所以这可以简化为:
- Person 1: R
- Person 2: G
所以在这种情况下,我们确切地知道每个人会选择什么.
例2:
现在让我们添加一些复杂性.现在我们有4个人需要从2个红球,1个绿球和4个蓝球中选择.人1可以选择任何球,人2和3可以选择红色或绿色球,人4必须选择红色球.所以我们有以下选择:
- Person 1: RRGBBBB
- Person 2: RRG
- Person 3: RRG
- Person 4: RR
由于人4只有一种选择,我们知道那个人必须选择一个红球.因此,我们可以从所有其他人中消除1个红球:
- Person 1: RGBBBB
- Person 2: RG
- Person 3: RG
- Person 4: RR
然而,这是它变得非常棘手的地方.我们可以看到,第2和第3人必须选择一个红球和一个绿球,我们只是不知道哪一个会选择哪一个.但是,由于我们每个球只剩下1个,因此红色和绿色也可以作为选项从第1个人中删除:
- Person 1: BBBB
- Person 2: RG
- Person 3: RG
- Person 4: RR
现在,我们可以使用以下选项从每个条目中删除重复项:
- Person 1: B
- Person 2: RG
- Person 3: RG
- Person 4: R
我们知道人1和人4的选择,而人2和3可以选择红色和绿色.
为了解决这个问题,我所做的就是循环人们,首先如果人们只有一个球类型,从阵列中删除那个人并将其放入结果数组中(因为我知道这是那个人必须选择的)然后如果存在,则从阵列中的每个其他人移除该球类型中的一个.
在此之后,在我看来,规则是:
If there are
$n
number of people who all have the same$n
number of
options (or a subset of them),these options can be removed
from all other people,where$n
is less than the total number of people.
所以我所做的就是再次遍历所有人,并检查具有相同选项的其他人(或这些选项的子集),如果这等于该人的选项总数,请从选项中删除所有其他人.
- // The quantity of each ball
- $balls = array(
- 'r' => 1,'g' => 1,'b' => 1,'k' => 1,);
- // The options available for each person
- $options = array(
- array('r','g','b','k'),array('r','g'),'b'),array('b',);
- // Put both of these together into one array
- $people = [];
- foreach ($options as $option) {
- $person = [];
- foreach ($option as $ball_key) {
- $person[$ball_key] = $balls[$ball_key];
- }
- $people[] = $person;
- }
- print_r($people);
- // This produces an array like:
- // Array
- // (
- // [0] => Array
- // (
- // [r] => 2
- // [g] => 1
- // [b] => 4
- // )
- //
- // [1] => Array
- // (
- // [r] => 2
- // [g] => 1
- // )
- //
- // [2] => Array
- // (
- // [r] => 2
- // [g] => 1
- // )
- //
- // [3] => Array
- // (
- // [r] => 2
- // )
- //
- // )
- // This will be used to hold the final result
- $results = [];
- do {
- // If anything changes,this needs to be set to true. Any time anything
- // changes we loop through everything again in case it caused a cascading
- // effect
- $has_change = false;
- // Step 1:
- // Find out if there are any people who have only one option and remove it
- // from the array and add it to the result and subtract one from all other
- // people with this option
- foreach ($people as $p_index => $p_options) {
- if (count($p_options) === 1) {
- $color = key($p_options);
- foreach ($people as $p_index_tmp => $p_options_tmp) {
- // It's the current person,so skip it
- if ($p_index_tmp === $p_index) {
- continue;
- }
- if (isset($p_options_tmp[$color])) {
- // Subtract 1 from this color from this person and if zero,// remove it.
- if (--$people[$p_index_tmp][$color] === 0) {
- unset($people[$p_index_tmp][$color]);
- }
- $has_change = true;
- }
- }
- // Add to results array and remove from people array
- $results[$p_index] = array($color => 1);
- unset($people[$p_index]);
- }
- }
- // Step 2:
- // If there are $n number of people who all have the same $n number of
- // options (or a subset of them),these options can be removed
- // from all other people,where $n is less than the total number of people
- foreach ($people as $p_index => $p_options) {
- $num_options = array_sum($p_options);
- if ($num_options < count($people)) {
- // Look for other people with no different options from the ones
- // that this person has
- $people_with_same_options = [];
- foreach ($people as $p_index_tmp => $p_options_tmp) {
- foreach (array_keys($p_options_tmp) as $color) {
- if (array_search($color,array_keys($p_options)) === false) {
- // This color was not found in the options,so we can
- // skip this person.
- // (Make sure we break out of both foreach loops)
- continue 2;
- }
- }
- // This person has all the same options,so append to the array
- $people_with_same_options[] = $p_index_tmp;
- }
- // Remove these options from the other people if the number of
- // people with only these options is equal to the number of options
- if (count($people_with_same_options) === $num_options) {
- foreach ($people as $p_index_tmp => $p_options_tmp) {
- if (array_search($p_index_tmp,$people_with_same_options) === false) {
- foreach (array_keys($p_options) as $option) {
- unset($people[$p_index_tmp][$option]);
- $has_change = true;
- }
- }
- }
- }
- }
- }
- }
- while ($has_change === true);
- // Combine any remaining people into the result and sort it
- $results = $results + $people;
- ksort($results);
- print_r($results);
这会产生以下结果:
- Array
- (
- [0] => Array
- (
- [b] => 1
- )
- [1] => Array
- (
- [r] => 1
- [g] => 1
- )
- [2] => Array
- (
- [r] => 1
- [g] => 1
- )
- [3] => Array
- (
- [r] => 1
- )
- )
例3:
此示例不适用于上述代码.假设有1个红球,1个绿球,1个蓝球,1个黄球和4个人.人1可以选择任何球,人2可以选择红色或绿色,人3可以选择绿色或蓝色,人4可以选择红色或蓝色.
在视觉上这看起来像:
- Person 1: RGBY
- Person 2: RG
- Person 3: GB
- Person 4: RB
由于红色,绿色和蓝色3种颜色是2,3和4人的唯一选择,因此它们完全包含在这3个人中,因此它们都可以从人1中消除,这意味着人1必须选择黄色.如果第一个人选择黄色的东西,那么其他人就不可能选择他们的球.
把它放到我的PHP程序中,我有这些输入值:
- // The quantity of each ball
- $balls = array(
- 'r' => 1,'y' => 1,'y'),);
但是我想不出如何循环查找这样的案例而不迭代每个可能的人组合.有什么想法可以做到这一点?
所以,以下看起来(不可否认)非常丑陋,除了你的三个例子之外,我还没有测试过它,但是在这里:
- class Ball {
- private $color;
- public function __construct($color) {
- $this->color = $color;
- }
- public function getColor() {
- return $this->color;
- }
- }
- class Ball_resource extends Ball {
- private $num_available;
- public function __construct($color,$number) {
- parent::__construct($color);
- $this->num_available = $number;
- }
- public function take() {
- $this->num_available--;
- }
- public function isExhausted() {
- return $this->num_available <= 0;
- }
- }
- class Person {
- /**
- *
- * @var Ball
- */
- private $allowed_balls = array();
- public function addConstraint($color) {
- $this->allowed_balls[$color] = new Ball($color);
- return $this;
- }
- public function getConstraints() {
- return $this->allowed_balls;
- }
- public function getNumberOfConstraints() {
- return count($this->allowed_balls);
- }
- /**
- * return true if removal was successful; false otherwise
- */
- public function removeConstraint(Ball $ball) { // todo remove
- if (isset ($this->allowed_balls [$ball->getColor()])) {
- unset ($this->allowed_balls [$ball->getColor()]);
- return true;
- }
- else {
- // this means our puzzle isn't solvable
- return false;
- }
- }
- }
- class Simplifier {
- /**
- *
- * @var Person
- */
- private $persons = array ();
- /**
- *
- * @var Ball_resource
- */
- private $availableBalls = array ();
- public function addPerson(Person $person) {
- $this->persons[] = $person;
- return $this;
- }
- public function addBallRessource(Ball_resource $ball_resource) {
- $this->availableBalls[] = $ball_resource;
- return $this;
- }
- public function getChoices() {
- $queue = $this->persons; // shallow copy
- while (count($queue) > 0) {
- // find most constrained person(s)
- $numberOfConstraints = 1; // each person must have at least one constraint
- while (true) {
- $resolve_queue = array();
- foreach($queue as $person) {
- if ($person->getNumberOfConstraints() === $numberOfConstraints) {
- $resolve_queue[] = $person;
- }
- }
- // find mutually dependent constraint groups connected with a person
- $first_run = true;
- foreach ($resolve_queue as $startPerson) {
- // check if we havent already been removed via dependencies
- if ($first_run || !self::contains($queue,$startPerson)) {
- $dependent_persons = $this->findMutuallyDependentPersons($startPerson,$resolve_queue);
- // make a set out of their combined constraints
- $combinedConstraints = $this->getConstraintsSet($dependent_persons);
- $this->adjustResources($dependent_persons);
- $this->removeFromQueue($dependent_persons,$queue);
- // substract each ball of this set from all less constrained persons
- $this->substractConstraintsFromLessConstrainedPersons($queue,$combinedConstraints,$numberOfConstraints);
- $first_run = false;
- continue 3;
- }
- }
- $numberOfConstraints++;
- }
- }
- return $this->persons; // has been altered implicitly
- }
- private static function contains(array $haystack,Person $needle) {
- foreach ($haystack as $person) {
- if ($person === $needle) return true;
- }
- return false;
- }
- private function findMutuallyDependentPersons(Person $startPerson,array $persons) {
- // add recursion
- $output = array();
- //$output[] = $startPerson;
- foreach($persons as $person) {
- foreach ( $person->getConstraints () as $constraint ) {
- foreach ( $startPerson->getConstraints () as $targetConstraint ) {
- if ($constraint->getColor () === $targetConstraint->getColor ()) {
- $output [] = $person;
- continue 3;
- }
- }
- }
- }
- return $output;
- }
- private function getConstraintsSet(array $persons) {
- $output = array();
- foreach ($persons as $person) {
- foreach ($person->getConstraints() as $constraint) {
- foreach($output as $savedConstraint) {
- if ($savedConstraint->getColor() === $constraint->getColor()) continue 2;
- }
- $output[] = $constraint;
- }
- }
- return $output;
- }
- private function substractConstraintsFromLessConstrainedPersons(array $persons,array $constraints,$constraintThreshold) {
- foreach ($persons as $person) {
- if ($person->getNumberOfConstraints() > $constraintThreshold) {
- foreach($constraints as $constraint) {
- foreach($this->availableBalls as $availableBall) {
- if ($availableBall->isExhausted()) {
- $person->removeConstraint($constraint);
- }
- }
- }
- }
- }
- }
- private function adjustResources(array $persons) {
- foreach($persons as $person) {
- foreach($person->getConstraints() as $constraint) {
- foreach($this->availableBalls as &$availableBall) {
- if ($availableBall->getColor() === $constraint->getColor()) {
- $availableBall->take();
- }
- }
- }
- }
- }
- private function removeFromQueue(array $persons,array &$queue) {
- foreach ($persons as $person) {
- foreach ($queue as $key => &$availablePerson) {
- if ($availablePerson === $person) {
- unset($queue[$key]);
- }
- }
- }
- }
- }
整个事情被称为这样:
- // Example 2
- {
- $person1 = new Person();
- $person1->addConstraint("R")->addConstraint("R")->addConstraint("G")->addConstraint("B")->addConstraint("B")->addConstraint("B")->addConstraint("B");
- $person2 = new Person();
- $person2->addConstraint("R")->addConstraint("R")->addConstraint("G");
- $person3 = new Person();
- $person3->addConstraint("R")->addConstraint("R")->addConstraint("G");
- $person4 = new Person();
- $person4->addConstraint("R")->addConstraint("R");
- $redBalls = new Ball_resource("R",2);
- $greenBalls = new Ball_resource("G",1);
- $blueBalls = new Ball_resource("B",4);
- $simplifier = new Simplifier();
- $simplifier->addPerson($person1)->addPerson($person2)->addPerson($person3)->addPerson($person4);
- $simplifier->addBallRessource($redBalls)->addBallRessource($greenBalls)->addBallRessource($blueBalls);
- $output = $simplifier->getChoices();
- print_r($output);
- }
同样对于例3:
- // Example 3
- {
- $person1 = new Person();
- $person1->addConstraint("R")->addConstraint("G")->addConstraint("B")->addConstraint("Y");
- $person2 = new Person();
- $person2->addConstraint("R")->addConstraint("G");
- $person3 = new Person();
- $person3->addConstraint("G")->addConstraint("B");
- $person4 = new Person();
- $person4->addConstraint("R")->addConstraint("B");
- $redBalls = new Ball_resource("R",1);
- $greenBalls = new Ball_resource("G",1);
- $yellowBalls = new Ball_resource("Y",1);
- $simplifier = new Simplifier();
- $simplifier->addPerson($person1)->addPerson($person2)->addPerson($person3)->addPerson($person4);
- $simplifier->addBallRessource($redBalls)->addBallRessource($greenBalls)->addBallRessource($blueBalls)->addBallRessource($yellowBalls);
- $output = $simplifier->getChoices();
- print_r($output);
- }
为简洁起见,我省略了原始输出.但是对于第二个例子,它基本上等于你在问题中的最后一个列表,而对于例3,它产生相当于:
- Person 1: Y
- Person 2: RG
- Person 3: GB
- Person 4: RB