Google的recaptcha文档并没有像我想象的那样有用,这有点奇怪.我被要求采用当前现有的表格(每天发送几次垃圾邮件)并使用Google的新回程更新.旧的验证码有很多教程,但对于新的验证码却没有那么多.我基本上只想要一个简单的表单来捕获名称,电子邮件,消息,然后用recaptcha替换我当前的“反机器人字段”(我使用的字段基本上问你2 2是什么,如果你输入任何东西,但4,它不会发送).如果必填字段有效且recaptcha有效,那么我希望它向我发送一封包含表单字段内容的电子邮件.
我经历了简单的步骤:
>注册我的网站获取密钥
>在我的head标签内添加了这个片段:
<script src='https://www.google.com/recaptcha/api.js'></script>
<div class="g-recaptcha" data-sitekey="#MYKEY#"></div>
在这一点上,recaptcha正好显示出来.但服务器端部分有点令人困惑.
这是我更新的联系表格,其中包含recaptcha:
<form method="post" action="contact-post.PHP"> <label>Your Name (required):</label> <input name="name" type="text" placeholder="Enter your name here"> <label>Email Address (required):</label> <input name="email" type="email" placeholder="Enter your email address here"> <label>Your Message (required):</label> <textarea name="message" placeholder="Write your message here"></textarea> <div style="margin-top:20px;" class="g-recaptcha" data-sitekey="#MYKEY#"></div> <input id="submit" name="submit" type="submit" value="Submit Form"> </form>
这是我当前的POST页面(我不确定在recaptcha代码中添加的位置):
<?PHP $name = $_POST['name']; $email = $_POST['email']; $message = $_POST['message']; $human = $_POST['human']; $from = 'From: My Website'; $to = 'myemail@gmail.com'; $subject = 'Request Form'; $body = "Name: $name \n E-Mail: $email \nMessage:\n$message"; if ($_POST['submit']) { if ($email != '') { if ($human == '4') { if (mail ($to,$subject,$body,$from)) { echo '<p>You have successfully submitted your information to PS4RS. Subscribers to our mailing list will begin to periodically receive updates.</p>'; } else { echo '<p>Something went wrong,go back and try again!</p><p><input type="button" value="Go Back" onclick="history.back(-1)" class="goback" /></p>'; } } else if ($_POST['submit'] && $human != '4') { echo '<p>You answered the anti-spam question incorrectly!</p><p><input type="button" value="Go Back" onclick="history.back(-1)" class="goback" /></p>'; } } else { echo '<p>You need to fill in all required fields!!</p><p><input type="button" value="Go Back" onclick="history.back(-1)" class="goback" /></p>'; } } ?>
欢迎任何帮助.我觉得这可能是一个非常普通的人,人们试图将它实现到他们当前的工作形式.
看看这个链接:
https://developers.google.com/recaptcha/docs/verify
https://developers.google.com/recaptcha/docs/verify
简而言之,你应该提出要求
https://www.google.com/recaptcha/api/siteverify?secret=YOUR_SECRET&response=RESPONSE_CAME_FROM_YOUR_FORM&remoteip=USER_IP_ADDRESS
如果YOUR_SECRET是您在ReCAPTCHA站点上收到的密钥,则可以通过$_SERVER数组接收USER_IP_ADDRESS,并且RESPONSE_CAME_FROM_YOUR_FORM是与您的表单一起发送的字符串.它存储在$_POST [‘g-recaptcha-response’]中.
您可以通过file_get_contents($url)来完成
$data = file_get_contents("https://www.google.com/recaptcha/api/siteverify?secret=YOUR_SECRET&response=RESPONSE_CAME_FROM_YOUR_FORM&remoteip=USER_IP_ADDRESS");
在$data中,您将收到包含您要查找的成功字段的JSON对象.如果成功是错误的,那么它不是人类,你应该退出().我建议你在程序开头检查这个.
更新:
JSON对象的解码如下所示:
$data = json_decode($data); // This will decode JSON to object if(!$data->success) exit();
更新:
有时,file_get_contents($url)将无法设置安全的https连接.相反,你可以使用open_https_url($url)
使您的代码看起来像:
<?PHP $your_secret = "<secret_key_you_received_from_recaptcha_site>"; $client_captcha_response = $_POST['g-recaptcha-response']; $user_ip = $_SERVER['REMOTE_ADDR']; $captcha_verify = open_https_url("https://www.google.com/recaptcha/api/siteverify?secret=$your_secret&response=$client_captcha_response&remoteip=$user_ip"); $captcha_verify_decoded = json_decode($captcha_verify); if(!$captcha_verify_decoded->success) die('DIRTY ROBOT'); $name = $_POST['name']; $email = $_POST['email']; $message = $_POST['message']; $human = $_POST['human']; $from = 'From: My Website'; $to = 'myemail@gmail.com'; $subject = 'Request Form'; $body = "Name: $name \n E-Mail: $email \nMessage:\n$message"; if ($_POST['submit']) { if ($email != '') { if ($human == '4') { if (mail ($to,$from)) { echo '<p>You have successfully submitted your information to PS4RS. Subscribers to our mailing list will begin to periodically receive updates.</p>'; } else { echo '<p>Something went wrong,go back and try again!</p><p><input type="button" value="Go Back" onclick="history.back(-1)" class="goback" /></p>'; } } else if ($_POST['submit'] && $human != '4') { echo '<p>You answered the anti-spam question incorrectly!</p><p><input type="button" value="Go Back" onclick="history.back(-1)" class="goback" /></p>'; } } else { echo '<p>You need to fill in all required fields!!</p><p><input type="button" value="Go Back" onclick="history.back(-1)" class="goback" /></p>'; } } ?>