我必须处理重构,以减少
PHP中的代码行数,以过滤关联数组.
所以我在MysqL中选择DB,以获得一个关联数组.所以我的“对象”有一个类别和一个姓氏字段.
所以我在MysqL中选择DB,以获得一个关联数组.所以我的“对象”有一个类别和一个姓氏字段.
while ($row = MysqLi_fetch_array($result)) { $array[] = $row['category']; $array[] = $row['Surname']; }
我想从这个数组中获取,就像许多其他子数组一样,按类别划分.我的意思是类别数组标识可能是:
$categories = array("A","B","C","D");
所以我想要的是为每个类别获取一个数组,其中包含该类别的所有姓氏.
所以假设该方法有效,就像这样:
$arrayFiltered = method_filter($array_asso,"A");
最后我想要这样的东西:
foreach ($categories as &$value) { $arrayFiltered = method_filter($array_asso,$value); my_method_which_needs_the_filtered_array($arrayFiltered); }
预先感谢您的帮助.
警长的方法是最简单的.只是为了它,这是一个
原文链接:https://www.f2er.com/php/136624.htmlarray_filter()
的方法(以防你必须有一个未经过滤的数组):
$array = []; $categories = array("A","D"); while ($row = MysqLi_fetch_array($result)) { $item = [ 'category' => $row['category'],'surname' => $row['Surname'] ]; $array[] = $item; } $categorized = []; foreach ($categories as $category) { $categorized[$category] = array_filter($array,function($item) use ($category) { return $item['category'] == $category; }); }
这是一个概念证明,无需数据库连接:
$categories = array("A","D"); $array = [ ['category' => 'A','Surname' => 'A Name 1'],['category' => 'A','Surname' => 'A Name 2'],['category' => 'B','Surname' => 'B Name 1'],'Surname' => 'B Name 2'],'Surname' => 'B Name 3'],['category' => 'C','Surname' => 'C Name'],]; $categorized = []; foreach ($categories as $category) { $categorized[$category] = array_filter($array,function($item) use ($category) { return $item['category'] == $category; }); } print_r($categorized);
输出:
Array ( [A] => Array ( [0] => Array ( [category] => A [Surname] => A Name 1 ) [1] => Array ( [category] => A [Surname] => A Name 2 ) ) [B] => Array ( [2] => Array ( [category] => B [Surname] => B Name 1 ) [3] => Array ( [category] => B [Surname] => B Name 2 ) [4] => Array ( [category] => B [Surname] => B Name 3 ) ) [C] => Array ( [5] => Array ( [category] => C [Surname] => C Name ) ) [D] => Array ( ) )