所以我有一个json对象,其结构如下：
{
"John Doe": [
{
"childName": "Harry","childAge": 15,"childGender": "Male"
},{
"childName": "Sally","childAge": 9,"childGender": "Female"
},],"Miss Piggy": [
{
"childName": "Jane","childAge": 20,"childGender": "Female"
}
],
}
我想要做的是能够查询childName,childAge或childGender,并返回该子对象(如果已找到).
例如：
searchJson($jsonObj,'childName','Sally') // returns {"childName":"Sally","childAge":9,"childGender":"Female"}
在这方面最好的方法是什么？
function searchJson($obj,$field,$value) {
foreach($obj as $item) {
foreach($item as $child) {
if(isset($child->$field) && $child->$field == $value) {
return $child;
}
}
}
return null;
}
