<script type="text/javascript">
    $(document).on('submit','.ajaxform',function(e){
        e.preventDefault();

        var datastring = $(this).serialize();

        $.ajax({
            type: "POST",data: datastring,contentType: "application/json; charset={CHARSET}",dataType: "json",beforeSend: function(){
                console.log($(this).serialize());
            },success: function(data){
                alert('yes');
            },error: function(errMsg){
                alert('error');
            }
        });
    });
</script>
<form action="" id="register" name="register" class="ajaxform" method="post" enctype="multipart/form-data">

    <input type="text" name="username" value="" />
    <input type="password" name="password" value="" />

    <input type="hidden" name="action" value="register" />
    <input type="hidden" name="{TOKENID}" value="{TOKEN}" />

    <input type="submit" value="Register" />

</form>

提交后,我无法通过键入$_POST [‘username’]来获取输入字段值.

我检查了检查元素,我注意到有些不同.

Request URL:http://project0/member.PHP
Request Method:POST
Status Code:200 OK
...
...
Content-Type:application/json; charset=UTF-8
...
...
Request payload:
username=asd&password=asd&action=register&29cd5e5ca1=73050db390872eb7c3fc564206b961c59a6363d6

这就是为什么我只能输入$_POST [‘param’]来获取POST数据？如何返回POST数据而不是有效负载？