我似乎遇到了以下代码的问题.当查询没有返回任何内容时,我无法获取插入查询.但是当db中有一行时,else语句会正确运行.有人知道为什么会发生这种情况吗？
$query5 = $this->db->get_where('loggedstatus',array('userid_loggedstatus' => $userid));
if ($query5->num_rows() < 0) {
$data1 = array('isLoggedIn_loggedstatus' => 'yes','userid_loggedstatus' => $userid);
$this->db->insert('loggedstatus',$data1);
} else {
$data = array('isLoggedIn_loggedstatus' => 'yes');
$this->db->where('userid_loggedstatus',$userid);
$this->db->update('loggedstatus',$data);
}
您是否尝试过将此更改为if($query5-> num_rows()< 0){if to if($query5-> num_rows()< = 0){,只是想一想.它会有所不同,因为你告诉它只有在小于零的情况下才执行,但它可能等于零,你会跳到else语句. 并且仅针对CodeIgniter num_rows()引用：
/**
* Number of rows in the result set
*
* @return int
*/
public function num_rows()
{
if (is_int($this->num_rows))
{
return $this->num_rows;
}
elseif (count($this->result_array) > 0)
{
return $this->num_rows = count($this->result_array);
}
elseif (count($this->result_object) > 0)
{
return $this->num_rows = count($this->result_object);
}
return $this->num_rows = count($this->result_array());
}
