我想采用未知长度的和/或逻辑查询查询字符串：
$logic = 'elephants and tigers or dolphins and apes or monkeys and humans and gorillas and and 133322 or 2';
并将其解析为数组,我假设看起来像：
$parsed_to_or = array(
array('elephants','tigers'),array('dolphins','apes'),array('monkeys','humans','gorillas','133322'),array('2')
);
这是我到目前为止：
$logic_e = preg_split('/\s+/',$logic);
$or_segments = array();
$and_group = array();
foreach($logic_e as $fragment) {
if (preg_match('/^(and|&&)$/i',$fragment)) {
continue;
} elseif (preg_match('/^(or|\\|\\|)$/i',$fragment)) {
if (count($and_group)>0) {
$or_segments[] = $and_group;
$and_group = array();
} continue;
} else {
$and_group[] = $fragment;
continue;
}
}
if (count($and_group)>0) {
$or_segments[] = $and_group;
$and_group = array();
}
更新：添加了使用&& ;;的功能和||随地
原文链接：https://www.f2er.com/php/135359.html您可以执行以下操作：
<?PHP $logic = 'elephants && tigers || dolphins && apes || monkeys and humans and gorillas and && 133322 or 2'; $result = array(); foreach (preg_split('/ (or|\|\|) /',$logic) as $parts) { $bits = preg_split('/ (and|&&) /',$parts); for ($x=0; $x<count($bits); $x++) { $bits[$x] = preg_replace('/\s?(and|&&)\s?/','',$bits[$x]); } $result[] = $bits; } echo '<pre>'; var_dump($result);
这将导致以下结果：
array(4) {
[0]=>
array(2) {
[0]=>
string(9) "elephants"
[1]=>
string(6) "tigers"
}
[1]=>
array(2) {
[0]=>
string(8) "dolphins"
[1]=>
string(4) "apes"
}
[2]=>
array(4) {
[0]=>
string(7) "monkeys"
[1]=>
string(6) "humans"
[2]=>
string(8) "gorillas"
[3]=>
string(6) "133322"
}
[3]=>
array(1) {
[0]=>
string(1) "2"
}
}
