假设我已经声明了这样的命名空间：
<?PHP // File kitchen.PHP namespace Kitchen; ?>
为什么我仍然必须在我想使用kitchen.PHP的所有其他文件中包含该文件
PHP不知道kitchen.PHP驻留在Kitchen命名空间中吗？
谢谢你的回答.
命名空间使您可以非常轻松地为项目中的任何类创建自动加载器,因为您可以直接在调用中包含类的路径.
原文链接：https://www.f2er.com/php/135247.html<?PHP // Simple auto loader translate \rooms\classname() to ./rooms/classname.PHP spl_autoload_register(function($class) { $class = str_replace('\\','/',$class); require_once('./' . $class . '.PHP'); }); // An example class that will load a new room class class rooms { function report() { echo '<pre>' . print_r($this,true) . '</pre>'; } function add_room($type) { $class = "\\rooms\\" . $type; $this->{$type} = new $class(); } } $rooms = new rooms(); //Add some rooms/classes $rooms->add_room('bedroom'); $rooms->add_room('bathroom'); $rooms->add_room('kitchen');
然后在你的./rooms/文件夹中你有3个文件：
bedroom.PHP
bathroom.PHP
kitchen.PHP
<?PHP namespace rooms; class kitchen { function __construct() { $this->type = 'Kitchen'; } //Do something } ?>
然后报告类加载的类
<?PHP $rooms->report(); /* rooms Object ( [bedroom] => rooms\bedroom Object ( [type] => Bedroom ) [bathroom] => rooms\bathroom Object ( [type] => Bathroom ) [kitchen] => rooms\kitchen Object ( [type] => Kitchen ) ) */ ?>
希望能帮助到你
