如果我是正确的,SimpleTest将允许您断言
PHP错误被抛出.但是,根据文档,我无法弄清楚如何使用它.我想声明我传递给构造函数的对象是MyOtherObject的一个实例
@H_502_6@class Object { public function __construct(MyOtherObject $object) { //do something with $object } } //...and in my test I have... public function testConstruct_ExpectsAnInstanceOfMyOtherObject() { $notAnObject = 'foobar'; $object = new Object($notAnObject); $this->expectError($object); }
我哪里错了?