如果我是正确的,SimpleTest将允许您断言
PHP错误被抛出.但是,根据文档,我无法弄清楚如何使用它.我想声明我传递给构造函数的对象是MyOtherObject的一个实例
class Object {
public function __construct(MyOtherObject $object) {
//do something with $object
}
}
//...and in my test I have...
public function testConstruct_ExpectsAnInstanceOfMyOtherObject() {
$notAnObject = 'foobar';
$object = new Object($notAnObject);
$this->expectError($object);
}
我哪里错了？
类型提示抛出E_RECOVERABLE_ERROR,自PHP版本5.2以来可以被SimpleTest捕获.以下将捕获包含文本“必须是实例”的任何错误. PatternExpectation的构造函数采用perl正则表达式.
public function testConstruct_ExpectsAnInstanceOfMyOtherObject() {
$notAnObject = 'foobar';
$this->expectError(new PatternExpectation("/must be an instance of/i"));
$object = new Object($notAnObject);
}
