如何使用DISTINCT为total_time_driven_at_this_trip获取具有最高值的唯一用户ID,还从另一个基于user_id的属于关系的表中提取user_name？
我试过这个……
$this->set('tripNsws',$this->TripNsw->find('all',array('limit' => 20,'fields' => array('DISTINCT(TripNsw.user_id)','TripNsw.total_time_driven_at_this_trip'),'group' => array('TripNsw.user_id'),'order' => array('TripNsw.total_time_driven_at_this_trip desc'))));
但它不起作用.
我想你需要得到以下……
SELECT DISTINCT(user_id),`total_time_driven_at_this_trip` FROM `trip_nsws` order by `total_time_driven_at_this_trip` desc
// see below url
http://book.cakePHP.org/1.3/view/1018/find
array(
'conditions' => array('Model.field' => $thisValue),//array of conditions
'recursive' => 1,//int
'fields' => array('Model.field1','DISTINCT Model.field2'),//array of field names
'order' => array('Model.created','Model.field3 DESC'),//string or array defining order
'group' => array('Model.field'),//fields to GROUP BY
'limit' => n,//int
'page' => n,//int
'offset'=>n,//int
'callbacks' => true //other possible values are false,'before','after'
)
// or try this
function some_function() {
$total = $this->Article->find('count');
$pending = $this->Article->find('count',array('conditions' => array('Article.status' => 'pending')));
$authors = $this->Article->User->find('count');
$publishedAuthors = $this->Article->find('count',array(
'fields' => 'DISTINCT Article.user_id','conditions' => array('Article.status !=' => 'pending')
));
}
