这是我的代码：

function connect() {

    $serverName = DB_HOST; //serverName\instanceName
    $connectionInfo = array( "Database"=>DB_NAME,"UID"=>DB_USER,"PWD"=>DB_PASSWORD);
    $this->connection = sqlsrv_connect( $serverName,$connectionInfo);
    sqlsrv_connect( $serverName,$connectionInfo);


    if( $this->connection ) {
         echo "<br>Connection established.<br />";
    }else{
         echo "<br>Connection could not be established.<br />";
         die( print_r( sqlsrv_errors(),true));
    }       


}

连接建立的回声正在工作所有AOK那里！

现在当我做一个简单的查询时：

function query($sql) {
    if ($this->debug) {
        echo $sql . "<br />";
    }       
    $this->sql = $sql;
    $this->recordset = sqlsrv_query($this->connection,$sql);

    if (!$this->recordset) {
        die('<br><br>Invalid query :<br><br><bold>' . $this->sql . '</bold><br><br>' . sqlsrv_errors());
    }

    echo "<br>rows = " . sqlsrv_num_rows($this->recordset);

我从上面的回声中得到了什么？有什么理由吗？或者你可以建议一个新的回声,我可以尝试调试这个？

我的数据库类中的所有代码都是从MysqL转换而来的,因此可能会有一些错误造成损坏！

我甚至尝试过一个超级简单的版本,所有代码在一起,它仍然是空白/假：

$server = DB_HOST;
$conn = sqlsrv_connect( $server,array( "Database"=>DB_NAME,"PWD"=>DB_PASSWORD) );
$stmt = sqlsrv_query( $conn,"SELECT * FROM MyTable");
$row_count = sqlsrv_num_rows($stmt);
echo "<br>row count = " . $row_count;
if ($row_count === false)
  echo "\nerror\n";
else if ($row_count >=0)
  echo "\n$row_count\n";
  die;