<?PHP $path = '/_Folder_/_SubFolder_'; ?>
当我们将网站从服务器移动到下一个网站时,我们的想法是简单地将$path定义更改为改造到新的开发服务器.目前,在我们调用包含的每个页面上,我们写道:
<?PHP include('../_includes/_css.PHP'); ?>
但我要做的是:
<?PHP include($path.'/_includes/_css.PHP'); ?>
我希望的结果是:
<?PHP include('/_Folder_/_SubFolder_/_includes/_css.PHP'); ?>
我一直在失败,导致:
Warning: include(/Folder/_SubFolder_/_includes/_css.PHP) [function.include]: Failed to open stream: No such file or directory in C:\Program Files\Apache Software Foundation\Apache2.2\htdocs\FREEDOM2012_FREEDOM2012_DEFAULT_\accommodations\guest-rooms.PHP on line 15
其他问题我仍然需要通过调用“../”来包含变量源.
<?PHP include('../_includes/_var.PHP'); ?>
如果有人对如何更有效地做到这一点有任何见解,我将非常感激.非常感谢您花时间,耐心和努力回应.