我有一个表有两个字段,引用另一个表的ID.我需要从两个字段的另一个表中提取名称.
例如.
Table1 worker1 = 2 (2 is key to other table) worker2 = 4Table2 ID NAME 1 Bill 2 Fred 3 John 4 Paul
我需要获得$worker1name = Fred和$worker2name = Paul.
所以我会说：
SELECT xxx,NAME?,NAME? FROM Table1 LEFT JOIN Table2 AS p1 ON Table1.worker1 = Table2.ID LEFT JOIN Table2 AS p2 ON Table1.worker2 = Table2.ID WHERE ... $table = MysqL_query(...); $rec = MysqL_fetch_assoc($table); $worker1name = $rec['???']; $worker2name = $rec['???'];
我在最后两个语句中插入什么来获取这两个名称.或者更准确地说,我必须添加到SELECT中以指定我想要从表2中调用两个不同版本的NAME字段吗？
您应该将字段别名如下：
原文链接：https://www.f2er.com/php/133597.htmlSELECT xxx,p1.NAME as p1name,p2.NAME as p2name FROM Table1 LEFT JOIN Table2 AS p1 ON Table1.worker1 = p1.ID LEFT JOIN Table2 AS p2 ON Table1.worker2 = p2.ID WHERE ...
