我看到这么多功能,但它只适用于
MySQL或Postgresql.我想要
PHP的等效逻辑.我在做一些比较,
就像我有创建时正在生成的这些数据.
就像我有创建时正在生成的这些数据.
Lat: 56.130366 Long: -106.34677099999
之后,我想检查这个坐标是否落在另一个坐标的半径之内,然后返回true,否则为false.
Lat: 57.223366 Long: -106.34675644699 radius: 100000 ( meters )
提前致谢!
谢谢您的帮助.下面是一个示例函数,它需要两组经度和纬度坐标,并返回两者之间的距离.
function getDistance( $latitude1,$longitude1,$latitude2,$longitude2 ) { $earth_radius = 6371; $dLat = deg2rad( $latitude2 - $latitude1 ); $dLon = deg2rad( $longitude2 - $longitude1 ); $a = sin($dLat/2) * sin($dLat/2) + cos(deg2rad($latitude1)) * cos(deg2rad($latitude2)) * sin($dLon/2) * sin($dLon/2); $c = 2 * asin(sqrt($a)); $d = $earth_radius * $c; return $d; } $distance = getDistance( 56.130366,-106.34677099999,57.223366,-106.34675644699 ); if( $distance < 100 ) { echo "Within 100 kilometer radius"; } else { echo "Outside 100 kilometer radius"; }