$user = Doctrine_Query::create()
->select('u.id,u.username,u.firstname,u.lastname')
->from('User u')
->orderby('u.id')
->execute();
$user = Doctrine_Query::create()
->select('u.id,u.username,u.firstname,u.lastname')
->from('User u')
->orderby('u.id')
->execute();
toArray()方法,使一个简单的数组只包含您感兴趣的数据,然后使用
json_encode将该PHP数组转换为JSON字符串.
这样的事情,我想：
$user = Doctrine_Query::create()
->select('u.id,u.lastname')
->from('User u')
->orderby('u.id')
->execute();
$userArray = $user->toArray();
$json = json_encode($userArray);
(未测试,但不应太远)…)
