使用()子句在
PHPUnit模拟中测试多个数组键的最佳方式是什么？
例如,要测试方法调用第二个参数是否包含一个’foo’键的数组：
$this->stubDispatcher->expects($this->once())
->method('send')
->with('className',$this->arrayHasKey('foo'));
我想做的是像$this-> arrayHasKey(‘foo’,’bar’),而实际上并不匹配数组的确切内容.
您可以直接将断言传递给 – > with(),但它们的名称不同.
有关列表,请查看源：https：//github.com/sebastianbergmann/PHPunit/blob/3.5/PHPUnit/Framework/Assert.PHP#L2097及以下.一切都不以“assert”开头,并返回一个新的PHPUnit_Framework_ *.
虽然我认为@ David的答案是有用的,我认为这种方法,使用logicalAnd()是一个更干净/更容易阅读.
$mock->expects($this->once())->method("myMethod")->with(
$this->logicalAnd(
$this->arrayHasKey("foo"),$this->arrayHasKey("bar")
)
);
工作实例
<?PHP class MyTest extends PHPUnit_Framework_TestCase { public function testWorks() { $mock = $this->getMock("stdClass",array("myMethod")); $mock->expects($this->once())->method("myMethod")->with( $this->logicalAnd( $this->arrayHasKey("foo"),$this->arrayHasKey("bar") ) ); $array = array("foo" => 1,"bar" => 2); $mock->myMethod($array); } public function testFails() { $mock = $this->getMock("stdClass",$this->arrayHasKey("bar") ) ); $array = array("foo" => 1); $mock->myMethod($array); } }
产量
PHPunit assertArrayKey.PHP PHPUnit 3.5.13 by Sebastian Bergmann. .F Time: 0 seconds,Memory: 6.50Mb There was 1 failure: 1) MyTest::testFails Expectation Failed for method name is equal to <string:myMethod> when invoked 1 time(s) Parameter 0 for invocation stdClass::myMethod(array( <string:foo> => <integer:1> )) does not match expected value. Failed asserting that an array has the key <string:bar>. /home/edo/test/assertArrayKey.PHP:27
