我有 :
- $date = $actualite['date'];
$actualite [‘date’]是一个TIMESTAMP
而且我想知道如何从这个时间戳中提取当天,然后是月份,然后是年份3个变量.
感谢您的帮助 :)
使用date_parse($actualite [‘date’]);它将返回包含日,月,年和其他项目的数组.
http://www.php.net/manual/en/function.date-parse.php
例:
- <?PHP
- print_r(date_parse("2006-12-12 10:00:00.5"));
- ?>
输出:
- Array
- (
- [year] => 2006
- [month] => 12
- [day] => 12
- [hour] => 10
- [minute] => 0
- [second] => 0
- [fraction] => 0.5
- [warning_count] => 0
- [warnings] => Array()
- [error_count] => 0
- [errors] => Array()
- [is_localtime] =>
- )