(对于与应用程序相关的答案,已经有一个类似的问题被问及超级用户的问题.问题在此发布,以收集相同的可编程解决方案) @H_502_1@在我的工作地点,护照尺寸的照片被扫描在一起,然后切成单独的图片,并保存与唯一的文件编号.目前我们使用Paint.net手动选择,剪切和保存图片.

@H_502_1@扫描文档Picasa截图：
(来自：谷歌图像搜索多个来源,公平)

@H_502_1@例如在Picasa 3.8中,点击查看>人,所有的脸都被显示出来,我被要求命名,我可以自动保存这些个人图片,名称不同的图片？

@H_502_1@更新

@H_502_1@所有我想做的是将上面的图片转换为个人图片.

@H_502_1@在上图中,我已经显示了Picasa 3.8如何检测到图像,并提示我将其命名.我不需要脸部识别,我只需要脸部检测. Picasa检测到单个图像,并在RHS上显示它们.这些单独的图像是我需要的. Picasa创建一个.ini文件,它保存包含单个面的坐标的十六进制值.

@H_502_1@这些个人面孔是我感兴趣的如果我可以有坐标,我可以从图片中裁剪所需的图像.

@H_502_1@SAMPLE.jpg

@H_502_1@ini内容

[SAMPLE.jpg]
faces=rect64(c18f4c8ef407851e),d4ff0a020be5c3c0;rect64(534a06d429ae627),dff6163dfd9d4e41;rect64(b9c100fae46b3046),e1059dcf6672a2b3;rect64(7b5105daac3a3cf4),4fc7332c107ffafc;rect64(42a036a27062a6c),ef86c3326c143248;rect64(31f4efe3bd68fd8),90158b3d3b65dc9b;rect64(327904e0614d390d),43cbda6e92fcb63e;rect64(4215507584ae9b8c),15b6a967e857f334;rect64(895d4efeb8b68425),5c4ff70ac70b27d3
backuphash=3660

@H_502_1@* ini文件似乎正在将脸标签的坐标保存为每个标签的rect64(534a06d429ae627),dff6163dfd9d4e41.
来自Picasa Help Site用户Technonath说

@H_502_1@@oedious wrote:- This is going to be
somewhat technical,so hang on.
* The number encased in rect64() is a 64-bit hexadecimal number.
* Break that up into four 16-bit numbers.
* Divide each by the maximum unsigned 16-bit number (65535) and you’ll have
four numbers between 0 and 1.
* The four numbers remaining give you relative coordinates for the face
rectangle: (left,top,right,bottom).
* If you want to end up with absolute coordinates,multiple the left and
right by the image width and the top
and bottom by the image height.

@H_502_1@上面的报价谈到了在rect64()中包含的数字,逗号后的括号内的数字呢？

@H_502_1@我问过一个相关的问题.答案也可以帮助你.
Get four 16bit numbers from a 64bit hex value

@H_502_1@Note: The
ini details are the same which picasa
generated for the particular image.

@H_502_1@Plus the question has been updated multiple times and may not be clear enough.

@H_502_1@在Picasa Help site有一些回应,我问同样的问题
来自该线程的答案之一是根据ini文件中的十六进制值获取坐标.以下代码在C#从esac从帮助网站.我可以在PHP中做同样的工作吗？

public static RectangleF GetRectangle(string hashstr)
{
    UInt64 hash = UInt64.Parse(hashstr,System.Globalization.NumberStyles.HexNumber);
    byte[] bytes = BitConverter.GetBytes(hash);

    UInt16 l16 = BitConverter.ToUInt16(bytes,6);
    UInt16 t16 = BitConverter.ToUInt16(bytes,4);
    UInt16 r16 = BitConverter.ToUInt16(bytes,2);
    UInt16 b16 = BitConverter.ToUInt16(bytes,0);

    float left = l16 / 65535.0F;
    float top = t16 / 65535.0F;
    float right = r16 / 65535.0F;
    float bottom = b16 / 65535.0F;

    return new RectangleF(left,right - left,bottom - top);
}

@H_502_1@PHP代码尝试将64位转换为1到0之间的数字

<?PHP
$dim = getimagesize("img.jpg");    
$hex64=array();
$b0="c18f4c8ef407851e";
$hex64[]=substr($b0,4);
$hex64[]=substr($b0,4,8,12,4);
$width=$dim[0];
$height=$dim[1];
foreach($hex64 as $hex16){
$dec=hexdec($hex16);
$divide=65536;
$mod=$dec%$divide;
$result=$dec/$divide;
$cordinate1=$result*$width;
$cordinate2=$result*$height;
echo "Remainder 1 : ".$mod." ; Result 1 :  ".$result."<br/>CO-ORDINATES : <B>".$cordinate1." ".$cordinate2."</B><br/>";
}
?>

@H_502_1@输出

@H_502_1@Remainder 1 : 49551 ; Result 1 :
0.75608825683594 CO-ORDINATES : 371.99542236328 396.94633483887 Remainder 1 : 19598 ; Result 1 :
0.29904174804688 CO-ORDINATES : 147.12854003906 156.99691772461 Remainder 1 : 62471 ; Result 1 :
0.95323181152344 CO-ORDINATES : 468.99005126953 500.4467010498 Remainder 1 : 34078 ; Result 1 :
0.51998901367188 CO-ORDINATES : 255.83459472656 272.99423217773

@H_502_1@所以我也有坐标,@Nirmal有shown how to crop them.现在接下来的步骤是解析picasa.ini的十六进制代码和文件名,并整合代码. Picasa当前没有通过api(或Do they?)提供十六进制代码.如果是这样,事情会更好.

@H_502_1@所以我们正在接近一个解决方案.谢谢大家,我希望我可以奖赏每个人(我不能,但不要害怕,并期待你的代表的一个尖峰)