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Swift JSONDecoder typeMismatch error2个
我对此很新手,但我一直试图弄清楚JSONDecoder如何为需要从MysqL数据库检索数据的登录功能起作用,如下面的代码所示,并且收到此错误.
我对此很新手,但我一直试图弄清楚JSONDecoder如何为需要从MysqL数据库检索数据的登录功能起作用,如下面的代码所示,并且收到此错误.
SWIFT代码:
- func testParseJson(){
- var request = URLRequest(url: URL(string: "https://test.PHP")!)
- request.httpMethod = "POST"
- let postString = ("Email=test&Password=test")
- print(postString)
- request.httpBody = postString.data(using: .utf8)
- let task = URLSession.shared.dataTask(with: request) { data,response,error in
- guard let data = data else { return }
- do {
- var responseString = String(data: data,encoding: .utf8)!
- print("new response string \(responseString)")
- let decoder = JSONDecoder()
- let newData = try decoder.decode(User.self,from: data)
- print(newData.Email)
- print(newData.UserType)
- } catch let err {
- print("Err",err)
- }
- }.resume()
- }
临时结构我一直试图使用:
- struct User: Decodable {
- let U_ID: String
- let Email: String
- let Password: String
- let UserType: String
- private enum CodingKeys: String,CodingKey {
- case U_ID
- case Email
- case Password
- case UserType
- }
- }
JSON响应字符串如下:
- [{"U_ID":"1","Email":"test","Password":"test","UserType":"Teacher"}]
任何帮助都将受到大力赞赏.
这里,JSON数据是对象数组.
更改
- try decoder.decode(User.self,from: data)
至
- try decoder.decode(Array<User>.self,from: data)
例:
- var users = [User]()
- let data = """
- [{"U_ID":"1","UserType":"Teacher"}]
- """.data(using: .utf8)
- do{
- users = try JSONDecoder().decode(Array<User>.self,from: data!)
- }catch{
- print(error.localizedDescription)
- }
- print(users.first?.Email)
注意:为了更好地理解,这是我在video系列中关于swift 4中的JSON解析