php – Swift4 JSONDecoderExpected解码Dictionary但找到了一个数组而不是[复制]

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参见英文答案 > Swift JSONDecoder typeMismatch error2个
我对此很新手,但我一直试图弄清楚JSONDecoder如何为需要从MysqL数据库检索数据的登录功能起作用,如下面的代码所示,并且收到此错误.

SWIFT代码

  1. func testParseJson(){
  2.  
  3. var request = URLRequest(url: URL(string: "https://test.PHP")!)
  4. request.httpMethod = "POST"
  5.  
  6. let postString = ("Email=test&Password=test")
  7. print(postString)
  8. request.httpBody = postString.data(using: .utf8)
  9.  
  10. let task = URLSession.shared.dataTask(with: request) { data,response,error in
  11. guard let data = data else { return }
  12. do {
  13. var responseString = String(data: data,encoding: .utf8)!
  14. print("new response string \(responseString)")
  15. let decoder = JSONDecoder()
  16. let newData = try decoder.decode(User.self,from: data)
  17. print(newData.Email)
  18. print(newData.UserType)
  19. } catch let err {
  20. print("Err",err)
  21. }
  22. }.resume()
  23. }

临时结构我一直试图使用:

  1. struct User: Decodable {
  2. let U_ID: String
  3. let Email: String
  4. let Password: String
  5. let UserType: String
  6.  
  7. private enum CodingKeys: String,CodingKey {
  8. case U_ID
  9. case Email
  10. case Password
  11. case UserType
  12. }
  13. }

JSON响应字符串如下:

  1. [{"U_ID":"1","Email":"test","Password":"test","UserType":"Teacher"}]

任何帮助都将受到大力赞赏.

这里,JSON数据是对象数组.

更改

  1. try decoder.decode(User.self,from: data)

  1. try decoder.decode(Array<User>.self,from: data)

例:

  1. var users = [User]()
  2.  
  3. let data = """
  4. [{"U_ID":"1","UserType":"Teacher"}]
  5. """.data(using: .utf8)
  6.  
  7. do{
  8. users = try JSONDecoder().decode(Array<User>.self,from: data!)
  9. }catch{
  10. print(error.localizedDescription)
  11. }
  12.  
  13. print(users.first?.Email)

注意:为了更好地理解,这是我在video系列中关于swift 4中的JSON解析

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