php – MYSQLI新查询在一段时间内获取

我现在正在制作一些有趣的网站,但我陷入了困境.

我想执行一个组任务,组中的任何成员都可以启动它.
该集团的所有人都将获得相同的黄金,经验
并分享同样的冷却时间.
我的数据库中有3个表(我只会显示重要信息)

Members:
username,level,experience,playergold

Levels:
level,required_experience

Groups:
leader,member_1,member_2,member_3,last_quest_started,quest_cooldown

Quests:
success_message,@R_404_159@_message,chance,minimum_experience,maximum_experience,minimum_gold,maximum_gold,cooldown

我想在组中更新last_quest_started和quest_cooldown,我想更新每个成员他/她的级别,经验,playergold

因此,在获得组成员的每个用户名后,任务数据,计算经验和金币.我用它来更新：

if($select_members_info_stmt = $MysqLi->prepare("SELECT members.username,members.level,members.experience,members.playergold,levels.required_experience FROM members INNER JOIN levels ON members.level = levels.level WHERE ((members.username = ?) OR (members.username = ?) OR (members.username = ?) OR(members.username = ?))"))
{
    $select_members_info_stmt->bind_param('ssss',$leader,$member_1,$member_2,$member_3);
    $select_members_info_stmt->execute();
    $select_members_info_stmt->bind_result($selected_username,$level,$experience,$playergold,$required_experience);
    while($select_members_info_stmt->fetch())
    {
        $now = time();

        if($update_user_stats_stmt = $MysqLi->prepare("UPDATE members SET level = ?,experience = ?,playergold = ? WHERE username = ?"))
        {
            $update_user_stats_stmt->bind_param('iiiiis',$new_level,$new_experience,$new_gold,$now,$cooldown,$selected_username);
            $update_user_stats_stmt->execute();
            if($update_user_stats_stmt->affected_rows == 0)
            {
                    echo '<div>Because of a system error it is impossible to perform a task,we apologize for this inconvience. Try again later.</div>';
            }
            $update_user_stats_stmt->close();
        }
        else                                
        {
            printf("Update user stats error: %s<br />",$MysqLi->error);
        }
    }
    $select_members_info_stmt->close();
    echo '<div>'.$success_message.'</div><br />';
}
else
{
    printf("Select members info error: %s<br />",$MysqLi_error);
}

但我一直在：

更新用户统计信息错误：命令不同步;你现在不能运行这个命令(4次,这是我的团队满员时的大小.)

我只是找不到解决方法来解决不同步错误,因为我无法关闭$select_members_info_stmt,因为它会停止提取.

请帮帮我,因为我真的不知道该怎么做.

你不能像这样嵌套你的execute().

最好的解决方案是将成员列表折叠成一个数组(),关闭连接,然后迭代该数组并更新每个记录.

它应该如下所示：

$select_members_info_stmt->bind_param('ssss',$member_3);
$select_members_info_stmt->execute();
$select_members_info_stmt->bind_result($selected_username,$required_experience);

$members = array();
while($select_members_info_stmt->fetch())
{
    // tossing into the array
    $members[] = array(
        'selected_username' =>$selected_username,'level' => $level,'experience' => $experience,'playergold' => $playergold,'required_experience' => $required_experience
    );
}
$select_members_info_stmt->close();

// Now iterate through the array and update the user stats
foreach ($members as $m) {
    if($update_user_stats_stmt = $MysqLi->prepare("UPDATE members SET level = ?,playergold = ? WHERE username = ?"))
    {
        // Note that you need to use $m['selected_username'] here. 
        $update_user_stats_stmt->bind_param('iiiiis',$m['selected_username']);
        $update_user_stats_stmt->execute();
        if($update_user_stats_stmt->affected_rows == 0)
        {
                echo '<div>Because of a system error it is impossible to perform a task,we apologize for this inconvience. Try again later.</div>';
        }
        $update_user_stats_stmt->close();
    }
    else                                
    {
        printf("Update user stats error: %s<br />",$MysqLi->error);
    }

}

原文链接：https://www.f2er.com/php/130339.html

php – MYSQLI新查询在一段时间内获取

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