mysql-是否可以在不使用关系的情况下联接原则ORM中的表？

假设有两个表.

Table X--
Columns:
     id         x_value

Table Y--
Columns:
     id        x_id      y_value

现在,我不想在学说类中定义关系,并且我想使用像这样的查询使用这两个表来检索一些记录：

Select x_value from x,y where y.id="variable_z" and x.id=y.x_id;

我无法弄清楚如何在准则orm中编写这样的查询

编辑：

表结构：

表格1：

CREATE TABLE IF NOT EXISTS `image` (
  `id` int(11) NOT NULL AUTO_INCREMENT,`random_name` varchar(255) NOT NULL,`user_id` int(11) NOT NULL,`community_id` int(11) NOT NULL,`published` varchar(1) NOT NULL,PRIMARY KEY (`id`)
 ) ENGINE=InnoDB  DEFAULT CHARSET=latin1 AUTO_INCREMENT=259 ;

表2：

  CREATE TABLE IF NOT EXISTS `users` (
  `id` int(11) NOT NULL AUTO_INCREMENT,`city` varchar(20) DEFAULT NULL,`state` varchar(20) DEFAULT NULL,`school` varchar(50) DEFAULT NULL,PRIMARY KEY (`id`)
 ) ENGINE=InnoDB  DEFAULT CHARSET=latin1 AUTO_INCREMENT=20 ;

查询我正在使用：

        $q = new Doctrine_Rawsql();

        $q  ->select('{u.*},{img.*}')
        ->from('users u LEFT JOIN image img ON u.id = img.user_id')
        ->addComponent('u','Users u')
        ->addComponent('img','u.Image img')
        ->where("img.community_id='$community_id' AND img.published='y' AND u.state='$state' AND u.city='$city
        ->orderBy('img.id DESC')
        ->limit($count+12)  
        ->execute();

我得到的错误：

 Fatal error: Uncaught exception 'Doctrine_Exception' with message 'Couldn't find class
 u' in C:\xampp\htdocs\fanyer\doctrine\lib\Doctrine\Table.PHP:290 Stack trace: #0 
 C:\xampp\htdocs\fanyer\doctrine\lib\Doctrine\Table.PHP(240): Doctrine_Table-   >initDefinition() #1 C:\xampp\htdocs\fanyer\doctrine\lib\Doctrine\Connection.PHP(1127): 
Doctrine_Table->__construct('u',Object(Doctrine_Connection_MysqL),true) #2 
C:\xampp\htdocs\fanyer\doctrine\lib\Doctrine\Rawsql.PHP(425): Doctrine_Connection-
>getTable('u') #3 C:\xampp\htdocs\fanyer\doctrine\models\Image.PHP(33):    Doctrine_Rawsql-
>addComponent('img','u.Image imga') #4   C:\xampp\htdocs\fanyer\community_images.PHP(31): 
  Image->get_community_images_gallery_filter(4,'AL','ALBERTVILLE') #5 {main} thrown      in 
    C:\xampp\htdocs\fanyer\doctrine\lib\Doctrine\Table.PHP  on line 290

最佳答案

尝试这样的事情：—

$q = new Doctrine_Rawsql();
$this->related_objects = $q->
        select('{o.name}')->
        from('tagset t1 JOIN tagset t2 ON t1.tag_id = t2.tag_id AND t1.object_id != t2.object_id JOIN object o ON t2.object_id = o.id')->
        addComponent('o','Object o')->
        where('t1.object_id = ?',$this->object->id)->
        groupBy('t2.object_id')->
        orderBy('COUNT(*) DESC')->
        execute();

原文链接：https://www.f2er.com/mysql/532042.html

mysql-是否可以在不使用关系的情况下联接原则ORM中的表？

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