php-获取2个数组之间的差

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我有2个搜索查询-一个将显示最近7天的内容.另一个将显示2周前的内容.
两者都很好.但是我想从第一个查询获取结果,并从第二个查询获取差异.然后显示带有差异的第一个查询.

@H_301_6@$result_account = $db->query(" SELECT nid,COUNT(cat) AS qty,dte,descript,cat,name,user FROM client_note AS cn JOIN client_note_tag_items AS cnti ON cnti.note_id = cn.nid JOIN client_note_tags AS cnt ON cnt.tag_id = cnti.tag_id WHERE dte >= DATE_SUB(CURDATE(),INTERVAL 7 DAY) AND name NOT LIKE 'Resolution%' GROUP BY cat ORDER BY qty DESC LIMIT 5 "); if($count_account = $result_account->num_rows) { while($row = $result_account->fetch_object()){ echo "<tr>"; echo "<td><h6>".$row->cat."</h6></td><td><h3 class='text-primary'>".$row->qty."</h3></td>"; echo "</tr>"; } } $result_prevIoUs = $db->query("SELECT nid,user FROM client_note AS cn JOIN client_note_tag_items AS cnti ON cnti.note_id = cn.nid JOIN client_note_tags AS cnt ON cnt.tag_id = cnti.tag_id WHERE (dte BETWEEN DATE_SUB(CURDATE(),INTERVAL 21 DAY) AND DATE_SUB(CURDATE(),INTERVAL 14 DAY)) AND name NOT LIKE 'Resolution%' GROUP BY cat ORDER BY qty DESC LIMIT 5"); if($count_prevIoUs = $result_prevIoUs->num_rows) { while($row_p = $result_prevIoUs->fetch_object()){ echo "<tr>"; echo "<td><h6>".$row_p->cat."</h6></td><td><h3 class='text-primary'>".$row_p->qty."</h3></td>"; echo "</tr>"; } }

第一个查询将导致:

@H_301_6@Category - Qty Baseball - 45 Football - 33 Soccer - 21 Hockey - 7 Basketball - 3

第二个查询将导致:

@H_301_6@Category - Qty Basketball - 38 Soccer - 28 Hockey - 16 Football - 12 Baseball - 12

现在我要这样显示

@H_301_6@Category - Qty Difference Baseball - 45 +33 Football - 33 +21 Soccer - 21 -7 Hockey - 7 -9 Basketball - 3 -35
最佳答案
我要做的是创建另一个数组,该数组在键-值的基础上保存来自第一个查询的值,而在下一个查询中,仅从数组中相应的条目中减去值.

我认为这是使用2个查询的最简单,最快的方法.

注意:我没有测试此代码.

注意2:我假设第一类运动缺失将被计为0

注意3:我编写的代码仅用于显示计算差异的方法.让我知道是否应该更新它,以提供您在那里所需的完全相同的输出.

@H_301_6@$results = array(); $result_account = $db->query("SELECT nid,user FROM client_note AS cn JOIN client_note_tag_items AS cnti ON cnti.note_id = cn.nid JOIN client_note_tags AS cnt ON cnt.tag_id = cnti.tag_id WHERE `dte` >= DATE_SUB(CURDATE(),INTERVAL 7 DAY) AND name NOT LIKE 'Resolution%' GROUP BY cat ORDER BY qty DESC LIMIT 5"); if($count_account = $result_account->num_rows) { while($row = $result_account->fetch_object()){ //output this query results here $results[$row->cat] = $row->qty; } } $result_prevIoUs = $db->query("SELECT nid,INTERVAL 14 DAY)) AND name NOT LIKE 'Resolution%' GROUP BY cat ORDER BY qty DESC LIMIT 5"); if($count_prevIoUs = $result_prevIoUs->num_rows) { while($row_p = $result_prevIoUs->fetch_object()){ //output this query results here $results[$row_p->cat] = ((isset($results[$row_p->cat])) ? $results[$row_p->cat] : 0 ) - $row_p->qty; } } foreach( $results as $key => $result) { echo "<tr>"; echo "<td><h6>".$key."</h6></td><td><h3 class='text-primary'>".$result."</h3></td>"; echo "</tr>"; }

更新-显示第一周及其旁边的差异

你可以试试看我摆脱了foreach,仅使用查询循环来完成所有操作.

注意:同样,这是未经测试的代码

@H_301_6@$results = array(); $result_account = $db->query("SELECT nid,INTERVAL 7 DAY) AND name NOT LIKE 'Resolution%' GROUP BY cat ORDER BY qty DESC LIMIT 5"); $result_prevIoUs = $db->query("SELECT nid,INTERVAL 14 DAY)) AND name NOT LIKE 'Resolution%' GROUP BY cat ORDER BY qty DESC"); if($count_prevIoUs = $result_prevIoUs->num_rows) { while($row_p = $result_prevIoUs->fetch_object()){ //output this query results here $results[$row_p->cat] = $row_p->qty; } } if($count_account = $result_account->num_rows) { while($row = $result_account->fetch_object()){ $difference = $row->qty - ((isset($results[$row->cat])) ? $results[$row->cat] : 0 ); echo "<tr>"; echo "<td><h6>".$row->cat."</h6></td><td><h3 class='text-primary'>".$row->qty."</h3></td><td><h3 class='text-primary'>".$difference."</h3></td>"; echo "</tr>"; } }

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