下面是表格数据(一小块)基本上我想查询按照accoutn编号分组时具有最小original_date_ctr的行.@H_404_2@
我尝试过使用HAVING(MIN()),其中= Min()和其他方式没有运气.@H_404_2@
这里的正确结果会给我id_ctr 688,1204和1209@H_404_2@
@H_404_2@
id_ctr account_number_cus original_date_ctr mrc_ctr
------ ------------------ ----------------- ----------
688 20062 2008-05-17 138.97
1204 151604 2006-08-10 42000.00
1209 151609 2006-06-29 968.68
1367 20062 2011-10-27 207.88
1434 151609 2009-09-10 1469.62
1524 151604 2009-09-01 36999.99
1585 151609 2012-05-31 1683.88
最佳答案
您可以通过以下方式执行此操作：@H_404_2@
@H_404_2@
select t1.id_ctr,t1.account_number_cus,t1.original_date_ctr,t1.mrc_ctr
from yourtable t1
inner join
(
select min(original_date_ctr) as mindate,account_number_cus
from yourtable
group by account_number_cus
) t2
on t1.account_number_cus = t2.account_number_cus
and t1.original_date_ctr = t2.mindate