SELECT student_id,section,count( * ) as total
FROM raw_data r
WHERE response = 1
GROUP BY student_id,section
测试共有4个部分,每个部分都有不同的问题.我想知道,对于每个学生和每个部分,他们正确回答了多少问题(响应= 1).
但是,使用此查询,如果学生在给定部分中没有得到任何问题,那么我的结果集中将完全丢失该行.我怎样才能确保每个学生总共返回4行,即使一行的“总数”为0?
这是我的结果集的样子:
student_id section total
1 DAP--29 3
1 MEA--16 2
1 NNR--13 1 --> missing the 4th section for student #1
2 DAP--29 1
2 MEA--16 4
2 NNR--13 2 --> missing the 4th section for student #2
3 DAP--29 2
3 MEA--16 3
3 NNR--13 3 --> missing the 4th section for student #3
4 DAP--29 5
4 DAP--30 1
4 MEA--16 1
4 NNR--13 2 --> here,all 4 sections show up because student 4 got at least one question right in each section
感谢您的任何见解!
更新:我试过了
SELECT student_id,if(count( * ) is null,count( * )) as total
而这根本没有改变结果.其他想法?
更新2:由于以下回复,我得到了它的工作:
SELECT student_id,SUM(CASE WHEN response = '1' THEN 1 ELSE 0 END ) AS total
FROM raw_data r
WHERE response = 1
GROUP BY student_id,section
最佳答案
SELECT student_id,sum(case when response=1 then 1 else 0 end) as total
FROM raw_data_r GROUP BY student_id,section
请注意,没有WHERE条件.