该脚本是一个出勤登记簿,因此它为每个用户记录每次会议的出勤标记.
使用的三个表:
“球队”:
id | fullname | position | class | hidden
1 | Team | -- | black | 1
2 | Dan S | Team Manager | green | 0
3 | Harry P | Graphic Engineer | blue | 0
“寄存器”:
id | mid | uid | mark
1 | 1 | 2 | /
2 | 1 | 3 | I
3 | 2 | 1 | /
4 | 2 | 3 | /
“会议”:
id | maintask | starttime | endtime
1 | Organise Year Ahead | 1330007400 | 1330012800
2 | Gather Ideas | 1330612200 | 1330617600
3 | TODO | 1331217000 | 1331222400
有一个数据样本.我想做的是:
从寄存器中选择所有结果,由用户对它们进行分组,然后按会议开始时间对它们进行排序.但是,如果寄存器表中没有标记,我希望它显示“ – ”(如果需要可以通过PHP完成)所以预期结果如下:
fullname | mark | mid
Dan S | / | 1
Dan S | / | 2
Dan S | - | 3
Harry P | I | 1
Harry P | / | 2
Harry P | - | 3
我的SQL查询目前是这样的:
SELECT u.
fullname
,u.id
,r.mark
,r.mid
FROMteam
u FULL JOINregister
r ON r.uid
=u.id
LEFT JOINmeetings
m ON
r.mid
=m.id
GROUP BY u.id
ORDER BY m.starttime
ASC
You have an error in your sql Syntax; check the manual that
corresponds to your MysqL server version for the right Syntax to use
near ‘FULL JOINregister
r ON r.uid
=u.id
LEFT JOINmeetings
m
ON r.mid
=m.`id’ at line 1
但是,我无法看到它的问题:S
请有人帮忙,指出正确的方向或给我一个可能的解决方案.非常感激
担
回答:
查询有效:
SELECT
u.fullname,u.id as uid,if(r.uid = u.id,r.mark,'-') as mark,r.mid,'-') as mid,m.starttime
FROM
team u
CROSS JOIN
register r ON u.id = r.uid
LEFT OUTER JOIN
meetings m ON r.mid = m.id
WHERE
u.hidden = 0
GROUP BY
u.id,r.mid
ORDER BY
m.starttime,u.id ASC
最佳答案
MysqL不支持全外连接.至少到5.6版,你可以检查MySQL Join doc.交叉连接可能是一种解决方法:
原文链接:https://www.f2er.com/mysql/433057.htmlEDITED
SELECT
UxM.fullname,UxM.mid,UxM.starttime
FROM
( select u.id as uid,m.id as mid,u.fullname,m.starttime
from
team u
CROSS JOIN
meetings ) UxM
left join
register r
on UxM.uid = r.uid and UxM.mid = r.mid
ORDER BY
UxM.starttime ASC
如果这可以解决您的问题,请告诉我.
简化:
SELECT
u.fullname,u.id AS uid,COALESCE(r.mark,'-') AS mark,COALESCE(r.mid,'-') AS mid,m.id,m.starttime
FROM
team u
CROSS JOIN
meetings m
LEFT JOIN
register r
ON r.mid = m.id
AND r.id = u.uid
WHERE
u.hidden = 0
GROUP BY
m.id,u.id
ORDER BY
m.starttime,u.id