我有一个PHP / 5.2驱动的应用程序,它使用MysqL / 5.1下的事务,因此如果满足错误条件,它可以回滚多个插入.我有不同的可重用功能来插入不同类型的项目.到现在为止还挺好.

现在我需要对某些插入使用表锁定.正如官方手册所示,我使用SET autocommit = 0而不是START TRANSACTION,因此LOCK TABLES不会发出隐式提交.并且,如文档所述,解锁表隐式提交任何活动事务：

> http://dev.mysql.com/doc/refman/5.1/en/lock-tables-and-transactions.html

问题在于：如果我只是避免使用UNLOCK TABLES,那么第二次调用LOCK TABLES就会提交挂起的更改！

似乎唯一的方法是在一个语句中执行所有必需的LOCK表.这是一个主要的噩梦.

这个问题是否有明智的解决方法？

这是一个小测试脚本：

DROP TABLE IF EXISTS test;

CREATE TABLE test (
    test_id INT(10) UNSIGNED NOT NULL AUTO_INCREMENT,random_number INT(10) UNSIGNED NOT NULL,PRIMARY KEY (test_id)
)
COLLATE='utf8_spanish_ci'
ENGINE=InnoDB;


-- No table locking: everything's fine
START TRANSACTION;
INSERT INTO test (random_number) VALUES (ROUND(10000* RAND()));
SELECT * FROM TEST ORDER BY test_id;
ROLLBACK;
SELECT * FROM TEST ORDER BY test_id;



-- Table locking: everything's fine if I avoid START TRANSACTION
SET autocommit=0;
INSERT INTO test (random_number) VALUES (ROUND(10000* RAND()));
SELECT * FROM TEST ORDER BY test_id;
ROLLBACK;
SELECT * FROM TEST ORDER BY test_id;
SET autocommit=1;



-- Table locking: I cannot nest LOCK/UNLOCK blocks
SET autocommit=0;
LOCK TABLES test WRITE;
INSERT INTO test (random_number) VALUES (ROUND(10000* RAND()));
SELECT * FROM TEST ORDER BY test_id;
ROLLBACK;
UNLOCK TABLES; -- Implicit commit
SELECT * FROM TEST ORDER BY test_id;
SET autocommit=1;


-- Table locking: I cannot chain LOCK calls ether
SET autocommit=0;
LOCK TABLES test WRITE;
INSERT INTO test (random_number) VALUES (ROUND(10000* RAND()));
SELECT * FROM TEST ORDER BY test_id;
-- UNLOCK TABLES;
LOCK TABLES test WRITE; -- Implicit commit
INSERT INTO test (random_number) VALUES (ROUND(10000* RAND()));
SELECT * FROM TEST ORDER BY test_id;
-- UNLOCK TABLES;
ROLLBACK;
SELECT * FROM TEST ORDER BY test_id;
SET autocommit=1;