在此question中,TofuBeer在创建通用IterableEnumeration时遇到问题.
答案来自jcrossley3,指向该链接http://www.javaspecialists.eu/archive/Issue107.html几乎解决了问题.
我仍然没有一件事.正如埃里克森有效指出的那样,真正的问题是:
You cannot specify a wildcard when constructing a parameterized type
final IterableEnumeration<ZipEntry> iteratable
= new IterableEnumeration<ZipEntry>(zipFile.entries());
导致以下错误:
Main.java:19: cannot find symbol
symbol : constructor IterableEnumeration(java.util.Enumeration<capture#469 of ? extends java.util.zip.ZipEntry>)
location: class IterableEnumeration<java.util.zip.ZipEntry>
final IterableEnumeration<ZipEntry> iteratable = new IterableEnumeration<ZipEntry>( zipFile.entries());
^
1 error
但是JavaSpecialist中的示例可以工作:
IterableEnumeration<String> ie =
new IterableEnumeration<String>(sv.elements());
我可以发现的唯一区别是,在JavaSpecialists博客中,枚举来自一个Vector,其签名为:
public Enumeration<E> elements()
而失败的源于ZipFile,其签名为:
public Enumeration<? extends ZipEntry> entries()
最后,所有这些都被for-each构造和链接中建议的静态make方法吸收了
for(final ZipEntry entry : IterableEnumeration.make( zipFile.entries() )) {
if(!(entry.isDirectory())) {
names.add(entry.getName());
}
}
但!!该新闻简报的重点不是解决此问题,而是避免因为语法看起来很丑而需要指定泛型类型!
所以..我的问题是:
怎么了?
当参数是类型为<的Enumeration时,为什么不能创建IterableEnumeration实例?扩展SomeClass> ?以及为什么make for-each构造会吞没这个问题?!
为什么这样做:
for(final ZipEntry entry : IterableEnumeration.make( zipFile.entries() )) {
但这行不通吗?
final IterableEnumeration<ZipEntry> iteratable
= IterableEnumeration.make( zipFile.entries() );
import java.util.Enumeration;
import java.util.HashSet;
import java.util.Iterator;
import java.util.Set;
import java.util.zip.ZipEntry;
import java.util.zip.ZipFile;
import java.util.Vector;
public class Main {
private ZipFile zipFile;
public Set<String> entries() {
final Vector<ZipEntry> vector = new Vector<ZipEntry>();
// why this works.
//final IterableEnumeration<ZipEntry> iteratable = new IterableEnumeration<ZipEntry>( vector.elements() );
// but this do not.
//final IterableEnumeration<ZipEntry> iteratable = new IterableEnumeration<ZipEntry>( zipFile.entries() );
// nor this
final IterableEnumeration<ZipEntry> iteratable = IterableEnumeration.make( zipFile.entries() );
// And what's with the for-each that doesn't care about the type?
final Set<String> names = new HashSet<String>();
for(final ZipEntry entry : IterableEnumeration.make( zipFile.entries() )) {
if(!(entry.isDirectory())) {
names.add(entry.getName());
}
}
return (names);
}
}
class IterableEnumeration<T> implements Iterable<T> {
private final Enumeration<T> enumeration;
public IterableEnumeration(final Enumeration<T> e) {
enumeration = e;
}
public Iterator<T> iterator() {
return new Iterator<T>() {
public boolean hasNext() {
return (enumeration.hasMoreElements());
}
public T next() {
return (enumeration.nextElement());
}
public void remove() {
throw new UnsupportedOperationException("Cannot remove via an Enumeration");
}
};
}
// As suggested by http://www.javaspecialists.eu/archive/Issue107.html
// but doesn't help with: final IterableEnumeration<ZipEntry> iteratable = IterableEnumeration.make( zipFile.entries() );
public static <T> Iterable<T> make(Enumeration<T> en) {
return new IterableEnumeration<T>(en);
}
}
我想了解它!
最佳答案
我不确定foreach循环会发生什么,但是您需要将通配符添加到IterableEnumeration的声明中,以接受从ZipFile.entries()返回的未指定类型.
原文链接:https://www.f2er.com/java/533011.html更换
private final Enumeration<T> enumeration;
public IterableEnumeration(final Enumeration<T> e) {
enumeration = e;
}
public static <T> Iterable<T> make(Enumeration<T> en) {
return new IterableEnumeration<T>(en);
}
用
private final Enumeration<? extends T> enumeration;
public IterableEnumeration(final Enumeration<? extends T> e) {
enumeration = e;
}
public static <T> Iterable<T> make(Enumeration<? extends T> en) {
return new IterableEnumeration<T>(en);
}