java-为什么服务器没有看到客户端发送数据?

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为什么在serverSocket.accept()上什么也没发生?服务器从客户端获取数据,但是程序对方法serverSocket.accept()不执行任何操作

public void start() {
        try {
            Socket socket= serverSocket.accept();
            System.out.println("Client accepted");

            in = new DataInputStream(
                    new BufferedInputStream(socket.getInputStream()));
            String line = "";
                    try {
                    line = in.readUTF();
                    System.out.println(line);

                } catch (IOException i) {
                    System.out.println(i);
                }
        } catch (IOException e) {
            System.out.println(e);
        }
    }
最佳答案
serverSocket.accept();

直到连接插座为止.

Socket s = serverSocket.accept();

in = new DataInputStream(new BufferedInputStream(s.getInputStream()));

要么

socket = serverSocket.accept();
in = new DataInputStream(new BufferedInputStream(socket.getInputStream()));

编辑-29.03.2019 11.54

因此,我们知道:

serverSocket.accept();

阻塞您的线程.您可以在主线程中调用它.

...
successfulThreads = new AtomicInteger(0);
latch = new CountDownLatch(testcaseThreads);
gate = new CyclicBarrier(testcaseThreads + 1);

server = new Server(SOCKET_PORT);
server.start();  //<-- Your program blocks!!!
//  ||
//  || STOP! No execution of the code.
// \\//
//  \/
for (File testcaseFile : testcaseFiles) {
            new Thread(new MockClient(this,testcaseFile)).start();
}

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