给出以下XML(示例)：
我需要获取Variant和Version的值.我目前的方法是使用XPath,因为我不能依赖给定的结构.我所知道的是文档中某处有一个元素rsb：Version.
XPath xpath = XPathFactory.newInstance().newXPath();
String expression = "//Variant";
InputSource inputSource = new InputSource("test.xml");
String result = (String) xpath.evaluate(expression,inputSource,XPathConstants.STRING);
System.out.println(result);
然而,这不输出任何东西.我尝试了以下XPath表达式：
> //变体
> // Variant / text()
> // rsb：Variant
> // rsb：Variant / text()
什么是正确的XPath表达式？或者有更简单的方法来获得这个元素？
最佳答案
我建议只循环遍历文档以查找给定的标记
public static void main(String[] args) throws SAXException,IOException,ParserConfigurationException,TransformerException {
DocumentBuilderFactory docBuilderFactory = DocumentBuilderFactory
.newInstance();
DocumentBuilder docBuilder = docBuilderFactory.newDocumentBuilder();
Document document = docBuilder.parse(new File("test.xml"));
NodeList nodeList = document.getElementsByTagName("rsb:VersionInfo");
for (int i = 0; i < nodeList.getLength(); i++) {
Node node = nodeList.item(i);
if (node.getNodeType() == Node.ELEMENT_NODE) {
// do something with the current element
System.out.println(node.getNodeName());
}
}
}
编辑：Yassin指出它不会获得子节点.这应该指出你正确的方向让孩子们.
private static List