什么是
Java更快.直接多次访问数组索引,或将数组索引的值保存到新变量并使用它来进行后续计算？
访问索引
if ((shape.vertices[0].x >= fromX && shape.vertices[0].x <= toX) || // left side of shape in screen
(shape.vertices[0].x <= fromX && shape.vertices[0].x + shape.width >= fromX) || // right side of shape in screen
(shape.vertices[0].x >= fromX && shape.vertices[0].x + shape.width <= toX)) { // shape fully in screen
// ...
}
临时变量
float x = shape.vertices[0].x;
float y = shape.vertices[0].y;
if ((x >= fromX && x <= toX) || // left side of shape in screen
(x <= fromX && x + shape.width >= fromX) || // right side of shape in screen
(x >= fromX && x + shape.width <= toX)) { // shape fully in screen
// ...
}
解决方法
第二种方法肯定更快.但您可以使用final关键字提供更多帮助：
final float x = shape.vertices[0].x;
final float y = shape.vertices[0].y;
final int rightEdge = x + shape.width;
if ((x >= fromX && x <= toX) || // left side of shape in screen
(x <= fromX && rightEdge >= fromX) || // right side of shape in screen
(x >= fromX && rightEdge <= toX)) { // shape fully in screen
// ...
}
当然不是一个显着的改进(但仍然是一种改进,也使意图明确).你可以阅读这个讨论：http://old.nabble.com/Making-copy-of-a-reference-to-ReentrantLock-tt30730392.html#a30733348
